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Zanzabum
2 years ago
6

Carbon cycle diagram

Physics
1 answer:
sammy [17]2 years ago
6 0

Carbon cycle shows is the continous movement of carbon in elemental and combined states on earth.

Steps :-

☆ Carbon moves from the atmosphere to plants. ...

☆ Carbon moves from plants to animals. ...

☆ Carbon moves from plants and animals to soils. ...

☆ Carbon moves from living things to the atmosphere. ...

☆ Carbon moves from fossil fuels to the atmosphere when fuels are burned. ...

☆ Carbon moves from the atmosphere to the oceans.

~ Benhemin360

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QuestionDetails:
sleet_krkn [62]

To solve the two parts of this problem, we will begin by considering the expressions given for gravitational potential energy and finally kinetic energy (to find velocity). From the potential energy we will obtain its derivative that is equivalent to the Force of gravitational attraction. We will start considering that all the points on the ring are same distance:

r = \sqrt{x^2+R^2}

Then the potential energy is

U = \frac{-GMm}{\sqrt{x^2+R^2}}

PART A) The force is excepted to be along x-axis.

Therefore we take a derivative of U with respect to x.

F = -\frac{dU}{dx}

F = -\frac{d}{dx}(GMm(\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}}))

F = \frac{GMmx}{(x^2+R^2)^{3/2}}

This expression is the resultant magnitude of the Force F.

PART B) The magnitude of loss in potential energy as the particle falls to the center

U = GMm(\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}})

According to conservation of energy,

\frac{1}{2}mv^2 = GMm (\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}})

\therefore v = \sqrt{2GM(\frac{1}{R}-\frac{1}{x^2+R^2})}

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3 years ago
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