The answer to this question is true
Answer
given,
mass of the dragster = 835 Kg
initial speed, u = 0 m/s
final speed, v = 110 km/h = 110 x 0.278 = 30.58 m/s
time, t = 0.90 s
a) Change in momentum
Δ P = m v - m u
Δ P = 835 x ( 30.58 - 0 )
Δ P = 25534.3 kg.m/s
b) average force exerted on the car
change in momentum = Force x time
25534.3 = F x 0.9
F = 28371.44 N
c) The exerted force is due to friction because the motion of the dragster is because of friction.
The equation of motion that we can use in this case is:
t = d / v
where t is time, d is distance, v is velocity
Therefore calculating for t:
t = 3.5 km / (25 km / h)
<span>t = 0.14 h = 8.4 minutes</span>
Answer:

Explanation:
You need to look at this in 3 separate stages, and then sum thedistance from each stage:
Stage 1)
a=2
t=20
=0


We also need to find the final velocity 
Stage 2)
a=0
v=40
t=20


Stage 3)
a=-3
=40
=0

So the total distance is 