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scZoUnD [109]
4 years ago
7

If a 15g irregular shaped object is submerged in a graduated cylinder of water, the level rises from 10 ml to 25 ml, what is the

density of the object?
Physics
1 answer:
SashulF [63]4 years ago
6 0

Answer:

one im so sry i have no idea. I have been researshing for about 30min and i cant find anything im so sry:/

Explanation:

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A 5.0 A electric current passes through an aluminum wire of 4.0~\times~10^{-6}~m^2 cross-sectional area. Aluminum has one free e
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Answer: The electron number density (the number of electrons per unit volume) in the wire is 6.0 \times 10^{28} m^{-3}.

Explanation:

Given: Current = 5.0 A

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Density = 2.7 g/cm^{3}, Molar mass = 27 g

The electron density is calculated as follows.

n = \frac{density}{mass per atom}\\= \frac{\rho}{\frac{M}{N_{A}}}\\

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\rho = density

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N_{A} = Avogadro's number

Substitute the values into above formula as follows.

n = \frac{\rho \times N_{A}}{M}\\= \frac{2.7 g/cm^{3} \times 6.02 \times 10^{23}/mol}{27 g/mol}\\= \frac{16.254 \times 10^{23}}{27} cm^{3}\\= 0.602 \times 10^{23} \times \frac{10^{6} cm^{3}}{1 m^{3}}\\= 6.0 \times 10^{28} m^{-3}

Thus, we can conclude that the electron number density (the number of electrons per unit volume) in the wire is 6.0 \times 10^{28} m^{-3}.

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