First step: name the sides according to geometry standards, namely, the sides are named the same lowercase letter as the opposing angle. A revised diagram is shown.
Second step: we need to know the relationships of the trigonometric functions.
cosine(A)=cos(63) = adjacent / hypotenuse = AC/AB .................(1)
sine(A)=sin(63) = opposite / hypotenuse = CB/AB .......................(2)
We're given AB=7, so
using (1)
AC/AB=cos(63)
AC=ABcos(63)=7 cos(63) = 7*0.45399 = 3.17993 = 3.180 (to three dec. figures)
Using (2)
BC/AB=sin(63)
BC=ABsin(63) = 7 sin(63) = 7*0.89101 = 6.237 (to three dec. figures).
Answer:
<h3>The answer is - 1/3</h3>
Step-by-step explanation:
To find the common ratio of the sequence divide the next term by the previous term
That's
- 2 / 6 = - 1/3
2/3 ÷ -2 = 2/3 × -1/2 = - 1/3
Hence
The common ratio is - 1/3
Hope this helps you
which means
has no solution, and we can omit that factor.
This leaves us with
which occurs for
.
Nice job inputting the expression.
The cube root is a 1/3 power. The 4 in the denominator is a -4 power in the numerator. When we have powers of powers we multiply them all together. When we have a product to a power we have to raise each factor to the power.
We get to choose whether we want a fraction at the end or negative exponents. Because of the constant 16 in the denominator I chose fraction.
Answer: 1/(16p⁸)