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Karo-lina-s [1.5K]
3 years ago
15

A car of mass 1800 kg can be just be lifted. What is the least force that the electromagnet must use to lift the car? (1 g = 10

N/kg)
Physics
1 answer:
Doss [256]3 years ago
8 0

Answer:

<h2>f=a×m</h2>

m=1800kg

1800000g×10N/kg

18000000N force is required to life the car

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Answer:

The change in volume is 6.885\times 10^{- 5}\

Solution:

As per the question:

Coefficient of linear expansion of Copper, \alpha = 17\times 10^{- 6}\ K^{- 1}

Initial Temperature, T = 0^{\circ} = 273 K

Final Temperature, T' = 100^{\circ} = 273 + 100 = 373 K

Now,

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V' = V(1 + 3\alpha \Delta T)

where

V' = Final volume

V' - V= 0.0135\times 17\times 10^{- 6} \times (T' - T))

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3 years ago
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