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3 years ago

A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?

Physics

1 answer:

AleksandrR [38]3 years ago

4 0

Explanation:

It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.

So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.

U = qV

Since, the electric potential is directly proportional to the charge. Hence, when 0.2 $\mu C$ tends to replaced by 0.4 $\mu C$ then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.

Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.

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Answer:

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2 years ago

Two balls of mass 0.09 kg hang on strings attached to the same point on the ceiling. The balls are given charges Q that cause th

telo118 [61]

Answer:

Q = 6.33μC

Explanation:

To find the value of the charge Q you take into account both gravitational force and electric force over each ball. By symmetry you can use the fact that both balls experiences the same forces. Hence you only take into account the forces for one ball for the x component and y component:

$-Mg+Tcos\theta=0\\\\F_e-Tsin\theta=0$

M: mass of the ball = 0.09kg

T: tension of the string

F_e: electric force between charges

angle = 45°

The electric force is given by:

$F_e=k\frac{Q^2}{r^2}$

Q: charge of the balls

r: distance between balls = 2m

You divide both equation in order to eliminate the tension T:

$tan\theta=\frac{F_e}{Mg}=k\frac{Q^2}{Mgr^2}$

By doing Q the subject of the formula and replacing you obtain:

$Q=\sqrt{\frac{tan\theta Mgr^2}{k}}=\sqrt{\frac{tan45\°(0.09kg)(2m)^2}{(8.89*10^{9}Nm^2/C^2)}}=6.33*10^{-6}C=6.33\mu C$

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3 years ago

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2 years ago

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A person tries to lift each object with a force of 25 N, upward. Which

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Answer:

Option C. Objects 1 and 3 will not move, and objects 2 and 4 will accelerate

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Explanation:

The following data were obtained from the question:

OBJECT >>>>>>>>> WEIGHT (N)

1 >>>>>>>>>>>>>>>> 35

2 >>>>>>>>>>>>>>>> 23

3 >>>>>>>>>>>>>>>> 26

4 >>>>>>>>>>>>>>>> 18

Force (F) applied = 25 N

From the above, the force applied to each object is 25N. Thus the following can be concluded based on the data given above:

For object 1:

Weight = 35 N

Force applied = 25 N

Thus, the object will not move since the weight of the object is greater than the force applied

For object 2:

Weight = 23 N

Force applied = 25 N

Thus, the object will move since the force applied is greater than the weight of the object.

For object 3:

Weight = 26 N

Force applied = 25 N

Thus, the object will not move since the weight of the object is greater than the force applied.

For object 4:

Weight = 18 N

Force applied = 25 N

Thus, the object will move since the force applied is greater than the weight of the object.

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