A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?
1 answer:
Explanation:
It is known that electric field is responsible for creating electric potential. As a result, it depends only on the electric field and not on the magnitude of charge.
So, when a charge is increased by a factor of 2 then electric potential will remain the same. Since, expression to calculate the electric potential is as follows.
U = qV
Since, the electric potential is directly proportional to the charge. Hence, when 0.2 tends to replaced by 0.4
then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.
Thus, we can conclude that if that charge is replaced by a +0.4 µC charge then electric potential stays the same, but the electric potential energy doubles.
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Answer:
a An increase in the speed will lower the internal pressure
Explanation:
Bernoulli's fluid formula
where
P = Pressure
ρ = Density of fluid
g = Acceleration due to gravity
h = Height
v = Velocity of fluid
If there is no change in height then we get
According to the Bernoulli's principle when the speed of the fluid is larger in a region of streamline flow the pressure is smaller in that region. From the above equation it can be seen that increase in speed should simultaneously reduce pressure in order for their sum to be constant.