<span>Here I think you have to find the velocity in x and y components where x is east and y is north
So as air speed indicator shows the negative speed in y component and adding it in
air speed while multiplying with the direction component we will get the velocity as velocity is a vector quantity so direction is also required
v=-28 m/s y + 18 m/s (- x/sqrt(2) - y/sqrt(2))
solving
v= -12.7 m/s x-40.7 m/s y
if magnitude of velocity or speed is required then
speed= sqrt(12.7^2 + 40.7^2)
speed= 42.63 m/s
if angle is asked
angle = arctan (40.7/12.7)
angle = 72.67 degrees south of west</span>
Answer:
The speed of the ball is 42.5 m/s
Explanation:
The initial kinetic energy of the ball is:
= 85.75 J
The speed of the ball after leaving the bat is:

V=47.92 m/s
Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:





Newton's third law of motion states that for every action there is an equal and opposite reaction. The balloon travels in the opposite direction as the air escaping from it. So when gas is released from the balloon it pushes against the outside air and the outside air pushes back. As a result of this the rocket is propelled forward by the opposing force. This opposing force is thrust.
Hope this helps!
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Explanation:
Given that,
Mass of the rock climber, m = 90 kg
Original length of the rock, L = 16 m
Diameter of the rope, d = 7.8 mm
Stretched length of the rope, 
(a) The change in length per unit original length is called strain. So,

(b) The force acting per unit area is called stress.

(c) The ratio of stress to the strain is called Young's modulus. So,

Hence, this is the required solution.
Sum the forces in the y (upward) direction




Applying the kinematic equations of linear motion we have that the displacement as a function of the initial speed, acceleration and time is



Again through the kinematic equation of linear motion that describes velocity as the change of displacement in a given time, we have to



Therefore the horizontal distance between the target and the rocket should be 38.83m