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Roman55 [17]
3 years ago
13

A disc initially at rest experiences an angular acceleration of 3.11 rad/s for a time of 15.0 s. What will the angular speed of

the disc be at this time, in units of rad/s?
Physics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

The angular speed of the disc be at this time is 46.65 rad/s.

Explanation:

Given that,

Angular acceleration \alpha= 3.11\ rad/s^2

Time t =15.0 s

We will calculate the angular speed of the disc

A disc initially at rest.

So, \omega=0

Using rotational kinematics equation

\omega'=\omega+\alpha\ t

Where, \omega = initial angular speed

\omega' =final angular speed

\alpha = angular acceleration

Put the value in the equation

\omega'=0+3.11\times15

\omega'=46.65\ rad/s

Hence, The angular speed of the disc be at this time is 46.65 rad/s.

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Explain why 15yr old need more calcium than adults
Tom [10]

Answer:

When adolescents get enough calcium during the teen years, they can start out their adult lives with the strong bones and significantly reduce their risk for fractures as an adult. Inadequate calcium intake during adolescence and young adulthood puts individuals at risk for developing osteoporosis later in life.

8 0
3 years ago
Read 2 more answers
On an aircraft carrier, a jet can be catapulted from 0 to 240 km/h in 2.10 s. If the average force exerted by the catapult is 9.
Leya [2.2K]
<h2>Answer</h2>

The answer is 29495.3 kg

<h2>Explanation</h2>

As we know, the Newton's Second Law of Motion

Force = Mass * Acceleration

F = ma

The F exerted by catapult = 9.35 * 10^5

The Time is = 2.10 s

Velocity of the catapult = 240 km/h = 66.6 m/s   (240*1000 m /3600 s)

The mass of jet = ?

First detrmine the acceleration as

{/tex}Acceleration = Velocity/Time {/tex}

Acceleration = 66.6 ms^{-1}/2.1 s

Acceleration (a) =  31.7 ms^{-2}

Rearrange the formaula as

m= F/a

m= 9.35 * 10^5 N /31.7 ms^{-2}

m = 29495.3 kg

The mass will be 29495.3 kg

4 0
4 years ago
Glycerin at 30°C has a density of 1,260 kg/m3 and a viscosity of 0.630 Pa s. In a laboratory experiment, some glycerin is forced
Alekssandra [29.7K]

Answer:

Explanation:

Rate of flow of liquid through a tube can be expressed by the following expression

V = π P r⁴ / 8ηl

P is pressure difference between end of tube = 618 Pa

r , radius of tube = .5 x 10⁻²

η is viscosity of liquid flowing = .63  

l is length of tube = .10 m

V = 3.14 x 618 x (  .5 x 10⁻² )⁴ / (8 x .63 x .10 )

= 240.64 x 10⁻⁸ m³ /s

mass = 240.64 x 1260 x 10⁻⁸ kg / s

= 3.03 x 10⁻³ kg /s

= 3.03 gram /s .

5 0
3 years ago
A cheetah is resting when a hare traveling in a straight path passes at it's top speed of 25m/s. It takes the cheetah 1.5 second
timofeeve [1]

Answer:

a) 2.3 m/s^2

b) 33.3 s

c) 803 m

d) 0 m/s

Explanation:

We need to apply the accelerated motion formulas.

The acceleration is given by:

a=\frac{v_f-v_o}{t}\\\\a=\frac{45m/s-0m/s}{20s}\\\\a=2.3m/s^2

we need to calculate the time the cheetah takes to stop when it starts to decelerate:

v=vo+a*t\\\\t=\frac{v-v_o}{a}\\\\t=\frac{0-45m/s}{-4m/s^2}=11.3s\\\\t_t=20s+2s+11.3s=33.3s

We need to calculate the displacement for all of the stages:

stage 1:

x_1=\frac{1}{2}*a*t^2\\\\x_1=\frac{1}{2}*2.3m/s^2*(20)^2\\\\x_1=460m

stage 2:

x_2=v*t\\x_2=45m/s*2s=90m

stage 3:

x_3=v_o*t+\frac{1}{2}*a*t^2\\\\x_3=45m/s*(11.3s)-\frac{1}{2}*4m/s^2*(11.3)^2\\\\x_3=253m

The total displacement is given by:

d=x_1+x_2+x_3\\d=460m+90m+253m=803m

the final velocity of the cheetah is zero because the cheetah decelerates until stop.

4 0
4 years ago
PLEASE HELP ME!!
statuscvo [17]

The balanced chemical equation is 2 AlI₃ + 3 HgCl₂\rightarrow 2 AlCl₃ + 3 HgI₂ for the given chemical reaction.

<h3>What is chemical equation?</h3>

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

Learn  more about chemical equation,here:

brainly.com/question/28294176

#SPJ1

4 0
1 year ago
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