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Roman55 [17]
3 years ago
13

A disc initially at rest experiences an angular acceleration of 3.11 rad/s for a time of 15.0 s. What will the angular speed of

the disc be at this time, in units of rad/s?
Physics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

The angular speed of the disc be at this time is 46.65 rad/s.

Explanation:

Given that,

Angular acceleration \alpha= 3.11\ rad/s^2

Time t =15.0 s

We will calculate the angular speed of the disc

A disc initially at rest.

So, \omega=0

Using rotational kinematics equation

\omega'=\omega+\alpha\ t

Where, \omega = initial angular speed

\omega' =final angular speed

\alpha = angular acceleration

Put the value in the equation

\omega'=0+3.11\times15

\omega'=46.65\ rad/s

Hence, The angular speed of the disc be at this time is 46.65 rad/s.

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