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3 years ago

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A disc initially at rest experiences an angular acceleration of 3.11 rad/s for a time of 15.0 s. What will the angular speed of

the disc be at this time, in units of rad/s?

1 answer:

kolezko [41]3 years ago

6 0

Answer:

The angular speed of the disc be at this time is 46.65 rad/s.

Explanation:

Given that,

Angular acceleration $\alpha= 3.11\ rad/s^2$

Time t =15.0 s

We will calculate the angular speed of the disc

A disc initially at rest.

So, $\omega=0$

Using rotational kinematics equation

$\omega'=\omega+\alpha\ t$

Where, $\omega$ = initial angular speed

$\omega'$ =final angular speed

$\alpha$ = angular acceleration

Put the value in the equation

$\omega'=0+3.11\times15$

$\omega'=46.65\ rad/s$

Hence, The angular speed of the disc be at this time is 46.65 rad/s.

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(Rounded to three significant figures.)

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