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2 years ago

Under what condition(vector A + vector B)= (vector A) + (vector B) holds good?

Physics

1 answer:

romanna [79]2 years ago

6 0

Answer:

when angle between them is zero degree

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Simple physics (Final) (Pic provided)

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Answer:

15m/s

Explanation:

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2 years ago

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2 years ago

The potential of electrons in a circuit can be increased by _____.

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2 years ago

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Why a body in uniform velocity is zero acceleration ?

seropon [69]

Uniform velocity means no Net force and therefore no acceleration. Acceleration only happens when the velocity changes.

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2 years ago

A solid conducting sphere with radius R carries a positive total charge Q. The sphere is surrounded by an insulating shell with

Illusion [34]

Answer:

Explanation:

Volume of the insulating shell is,

$V_{shell}=\frac{4}{3}\pi(R^3_2-R^3_1)$

Charge density of the shell is,

$\rho=\frac{Q_{shell}}{\frac{4}{3}\pi(R^3_2-R^3_1)}$

Here, $R_2 =2R, R_1 =R \,and\, Q_{shell} =-Q$

$\rho=\frac{Q_{shell}}{\frac{4}{3}\pi((2R)^3-R^3)}=\frac{-3Q}{28\piR^3}$

The electric field is $E=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}$

For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.

For R <r <2R According to gauss law

$E(4\pi r^2)=\frac{Q}{\epsilon_0}+\frac{4\pi\rho}{3\epsilon_0}(r^3-R^3)$

substitute $\rho=\frac{-3Q}{28\piR^3}$

$E=\frac{2}{7\pi\epsilon_0}\frac{Q}{r^2}-\frac{Qr}{28\piR^3}$

The net charge enclosed for each r in this range is positive and the electric field is outward

For r>2R

Charge enclosed is zero, so electric field is zero

8 0

2 years ago