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love history [14]
3 years ago
11

Under what condition(vector A + vector B)= (vector A) + (vector B) holds good?

Physics
1 answer:
romanna [79]3 years ago
6 0

Answer:

when angle between them is zero degree

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As you heat a steak on a grill, what kind of energy are you increasing in the steak?
katrin2010 [14]
The correct answer to the question above is Thermal Energy. As you heat a steak on a grill, the kind of energy that you are increasing is Thermal Energy. Thermal energy is the energy that come from heat, since you are you grilling the steak which means there is fire underneath, it has thermal energy. 
8 0
3 years ago
A cannon launches a 4.0kg bowling ball with 50J of kinetic energy what is the bowling ball’s speed
kobusy [5.1K]

Explanation:

I will try to find the formula

4 0
3 years ago
Read 2 more answers
An electric charge q of mass m in an oscillating electric field Eosinot experiences force q Eosinot. Suppose it starts from rest
Masja [62]

Answer:

speed of the charge electric is  v = - (Eo q/m) cos t

Explanation:

The electric charge has a very small mass so it follows the oscillations of the electric field. We force ourselves on the load,

          F = q Eo sint

a) To find the velocity of the particle, let's use Newton's second law to find the acceleration and of this by integration the velocity

        F = ma

        q Eo sint = ma

        a = Eo q / m sint

        a = dv / dt

        dv = adt

        ∫ dv = ∫ a dt

        v-vo = I (Eoq / m) sin  t dt

        v- vo = Eo q / m (-cos t)

We evaluate the integral from the initial point, as the particle starts from rest Vo = 0, for t = 0

        v = - (Eo q / m) cos t

b) Kinetic energy

       

         K = ½ m v2

          K = ½ m (Eoq / m)²2 (sint)²

         K = ¹/₂  Eo² q² / m sin² t

c) The average kinetic energy over a period

          K = ½ m v2

         <v2> = (Eoq / m) 2 <cos2 t>

The average of cos2 t = ½, substitute and calculate

          K = ½ m (Eoq / m)²  ½

          K = ¼ Eo² q² / m

7 0
4 years ago
A small plane flies 40.0 km in a direction 60° north of east and then flies 30.0 km in a direction 15° north of east. Use the an
lana66690 [7]

Answer:

d= 64.7 km

\theta = 40.9^{o}

displacement vector=r_xi + r_yj =  48.9i + 42.4j

Explanation:

total distance = 40 + 30 = 70 km

during 1st flight

r_1 x = 40*cos60

r_1 x = 20 km

r_1 y = 40*sin60

r_1 y = 34.64 km

during 2nd flight

r_2 x = 30*cos15

r_2 x = 28.9 km

r_2 y = 30*sin15

r_2 y = 7.76 km

the two component of r are:

r_x = r_1x + r_2x = 20 + 28.9 = 48.9 km

r_y = r_1y + r_2y = 34.64 + 7.76 = 42.4 km

Geographical Direction \theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}

Displacement d= \sqrt{r_x^2 + r_y^2}

                     d = \sqrt{48.9^2+42.4^2} = 64.7 km

d= 64.7 km

displacement vector=r_xi + r_yj =  48.9i + 42.4j

8 0
3 years ago
A boy whirls a stone in a horizontal circle of radius 1.50m and at height 2.00m above level ground. The string breaks, and the s
Eddi Din [679]

Answer:

a_{cp}=162.2m/s^2

Explanation:

The time the stone takes to fall can be calculated considering only the vertical component with the formula:

y=y_0+v_{0y}t+\frac{a_yt^2}{2}

Taking the inital height as 0m and downward direction positive, since it departs from (vertical) rest we have:

y=\frac{gt^2}{2}

Which gives us a time:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(2m)}{(9.8m/s^2)}}=0.64s

Horizontally, on that time the stone travelled a distance x=10m, which means its horizontal speed was:

v_x=\frac{x}{t}=\frac{10m}{0.64s}=15.6m/s

Since <u>this speed is the tangential velocity</u> while whirling, the centripetal acceleration of the stone was:

a_{cp}=\frac{v_x^2}{r}=\frac{(15.6m/s)^2}{(1.5m)}=162.2m/s^2

7 0
3 years ago
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