Change in size because that just means that more is added rather than anything reacting
It's a dilute solution! So the answer would be C.
Answer:
4CHO + 3O2 → 4CO2 + 2H2O
Explanation:
4CHO + 3O2 → 4CO2 + 2H2O
Not sure how to explain but I hope this helps :)
There number of calories that are required to raise the temperature of 105 g of water from 30.0 c to 70.0 c is calculated as follows
Q(heat)= mass(m) x specific heat capacity of water ( 1 cal/g/c) x delta T ( change in temperature
delta T = 70.0- 30.0= 40.0 c
Q= 105 g x 1 cal/g/c x 40 c = 4200 calories is needed to raise temperature of water from 30 c to 70 c
4% mass / volume :
4 g ---------> 100 mL
1.2 g ------- ? mL
V = 1.2 * 100 / 4
V = 120 / 4
V = 30 mL
hope this helps!