1) Write the balanced chemical equation
4NH3 + 5O2 ----> 4NO + 6H2O
2) Write the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Write the proportions with the desired quantity of NO and the unknown quantity of O2
5 mol O2 / 4 mol NO = x / 18.0 mol NO
Solve for x: x = 18.0 mol NO * 5 mol O2 / 4 mol NO = 22.5 mol O2
4) Use the ideal gas equation to convert moles to volume
pV = nRT => V = nRT / p
n = 22.5 mol
R = 0.082 atm*liter / K * mol
T = 33 + 273.15 = 306.15 K
p = 874/760 atm = 1.15 atm
V = 22.5 mol * 0.082 atm*liter/K*mol * 306.15 K / 1.15 atm = 491.17 liter
Answer: 491 liters of O2
When E° cell is an electrochemical cell which comprises of two half cells.
So,
when we have the balanced equation of this half cell :
Al3+(aq) + 3e- → Al(s) and E°1 = -1.66 V
and we have also this balanced equation of this half cell :
Ag+(aq) + e- → Ag(s) and E°2 = 0.8 V
so, we can get E° in Al(s) + 3Ag (aq) → Al3+(aq) + 3Ag(s)
when E° = E°2 - E°1
∴E° =0.8 - (-1.66)
= 2.46 V
∴ the correct answer is 2.46 V
The number of protons is equal to the atomic number
