Answer:
When t=2.1753 & t=.5746 , h=27
Don't worry, I got you. Also, my calculator does too.
We set h equal to 27, because we want the height to be 27 when we solve for t.
That leaves us with:
27 = 7 + 44t - 16t^2
Simplify like terms,
20 = 44t - 16t^2
Move 20 onto the right side, so we can use quadratic equation
44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20
Using quadratic, you get
t=2.1753 & t=.5746
<u>poster confirmed : "It’s t=2.18 and t=0.57"</u>
Answer:
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Step-by-step explanation:
Given that when X denotes the errors in an experimental transmission channel, when checked by a certifier that detects missing pulses. follows the cumulative density function as given below:
Answer:
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Step-by-step explanation:
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