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3 years ago

Find the hcf 8x(x - 2) -2(x - 2)

Mathematics

2 answers:

cupoosta [38]3 years ago

8 0

Answer:

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charle [14.2K]3 years ago

3 0

We can see both terms have a (x-2) in them.

We can also see that 8 and 2 are both even so there is a 2 in common.

This means that the gcd or hcf or whatever you call it is 2(x-2)

**Just mentioning most of the time we call it the GCD(greatest common divisor) or the GCF(greatest common factor) and almost never uses hcf :)

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How many terms in 2-8+22 A. 1 B. 2 C. 3 D. 26

natima [27]

Answer:

6 is the answer.

is it right

4 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

Hence, the amount of oil was decreasing at 69300 barrels, yearly

7 0

3 years ago

What is the value of x in the equation 3x – y = 18, when y = 27?

atroni [7]

3x – y = 18

We start by plugging in 27 for y. The goal is to isolate x by itself to solve for x.

3x - 27 = 18

Then we add 27 to both sides of the equation

3x = 45

Lastly, we divide both sides by 3 to finally isolate x by itself and solve.

x = 15

3 0

3 years ago

Read 2 more answers

Explain how place value could be used to find the difference of $4.23 and $2.75

frozen [14]

I don't know if this is what you mean by your question but can be broken down by place value into 4, 0.20 and 0.03. 2.75 can be broken down into 2, 0.70, and 0.05. Then subtract the same place values from each and you will get 1.48

5 0

4 years ago

A store pays by the ounce to have different types of bracelets made and wants to categorize them by price. Drag each purchase to

olya-2409 [2.1K]

Answer: The first one goes under three, Second one goes in the third row, The third one goes in the third row also, I'm thinking the fourth one goes under the third row too, and I'm thinking the last one on the top goes in $1 per 2.5 ounces.

Step-by-step-exclamation : How I know this is because I did the math on my calculator and you can too to check my work ✔

4 0

3 years ago

Find the hcf 8x(x - 2) -2(x - 2)​

Find the hcf 8x(x - 2) -2(x - 2)