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Afina-wow [57]
3 years ago
12

What is the angle between a wire carrying an 8.40 A current and the 1.20 T field it is in, if 50.0 cm of the wire experiences a

magnetic force of 2.55 N? ° (b) What is the force (in N) on the wire if it is rotated to make an angle of 90° with the field? N
Physics
1 answer:
Elena L [17]3 years ago
6 0

Answer:

A. 30.38°

B 5.04N

Explanation:

Using

F= ILBsin theta

2 .55N= 8.4Ax 0.5mx 1.2T x sintheta

Theta = 30.38°

B. If theta is 90°

Then

F= 8.4Ax 0.5mx 1.2x sin 90°

F= 5.04N

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Explanation:

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2 years ago
Rupert (66 kg) is now in a full-pipe of radius 25 m, calculate the minimum speed at which Rupert can skate to ensure he will not
V125BC [204]

at the top most point if Rupert will not fall then normal force at the top point is almost zero for minimum speed

so here we can say

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now if

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v = \sqrt{Rg}

v = \sqrt{25 \times 9.8}

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A transformer has a primary coil with 375 turns of wire and a secondary coil with 1,875 turns. An AC voltage source connected ac
Sonbull [250]

Answer:

The rms voltage (in V) measured across the secondary coil is 459.62 V

Explanation:

Given;

number of turns in the primary coil, Np = 375 turns

number of turns in the secondary coil, Ns = 1875 turns

peak voltage across the primary coil, Ep = 130 V

peak voltage across the secondary coil, Es = ?

\frac{N_P}{N_s} = \frac{E_p}{E_s} \\\\E_s = \frac{N_sE_p}{N_p} \\\\E_s = \frac{1875*130}{375} \\\\E_s = 650 \ V

The rms voltage (in V) measured across the secondary coil is calculated as;

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Therefore, the rms voltage (in V) measured across the secondary coil is 459.62 V

7 0
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A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits th
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initially coin is at rest and then it drop for total time t = 1.5 s

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now from above equation

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v_f = 14.7 m/s

so it will hit the floor with speed 14.7 m/s

3 0
3 years ago
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