What is the angle between a wire carrying an 8.40 A current and the 1.20 T field it is in, if 50.0 cm of the wire experiences a
1 answer:
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Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s²
By using the formula:
v²= u²+ 2as
v²=0²+ 2×10×15
v²= 300
V= 10root over 3
For calculating time,
v= u+ at
10 root over 3 = 0+ 10t
10 root over= 10t
t = 1 root over 3
t = 1.73 s
The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.
Answer:(a)0,(b)1.061 kg-m/s
Explanation:
Given
mass of ball is 0.10 kg
Initial speed is 15 m/s
Maximum height reached by ball is h
final velocity =0
thus momentum of ball at maximum height is 0 as velocity is zero
For halfway to maximum height
where
v=10.61 m/s
Thus its momentum is