What is the angle between a wire carrying an 8.40 A current and the 1.20 T field it is in, if 50.0 cm of the wire experiences a
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To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.
An athlete at high performance inhales 4.0L of air at 1atm and 298K.
The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.
During inhalation, volume of water taken is
During exhalation, volume of water expelled is
During 40 breathes, total volume of water taken is
During 40 breathes, total volume of water expelled out is
Therefore resultant volume of water expelled out from the lung is
From the body through the lung we have that
Here,
P = Pressure
R= Gas ideal constant
T= Temperature
V = Volume
Replacing,
Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min