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serious [3.7K]
3 years ago
5

How hot, in degrees Celsius, would the air inside the balloon have to get in order for the balloon to lift off the ground? Assum

e the molar mass of air is 28.97 g/mol and its density is 1.20 kg/m3.
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

The temperature in degress Celsius is 52.25°C

Explanation:

According the equation:

V(\rho _{a}  -\rho _{t})g=mg\\\rho _{a}  -\rho _{t}=\frac{n}{V} =\frac{340}{2950} =0.115kg/m^{3}

\rho _{t}=\rho _{a}  -0.115=1.2-0.115=1.085kg/m^{3}

The temperature is:

T=\frac{P}{\rho _{t} R} =\frac{1.013x10^{5} }{1.085*287.05} =325.25K=52.25°C

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Based on the balanced chemical equation for the preparation of malachite, what is the composition of the bubbles formed when sod
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Explanation:

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3 0
3 years ago
Which contains more molecules: 1.00 mol, H2O2, 1.00 mol C2H2, or 1.00 mol CO?
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7 0
2 years ago
Determine the total enthalpy of the reactants and the total enthalpy of the products. Record these values in Table C.
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Answer:

See explanation

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The reaction equation is;

C3H8 (g) + 5O2(g) -------> 4H2O(g) + 3CO2(g)

From the formula;

Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)

Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)

Hence;

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5 0
2 years ago
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