Question

How hot, in degrees Celsius, would the air inside the balloon have to get in order for the balloon to lift off the ground? Assume the molar mass of air is 28.97 g/mol and its density is 1.20 kg/m3.

Answer 1

Answer:

The temperature in degress Celsius is 52.25°C

Explanation:

According the equation:

$V(\rho _{a} -\rho _{t})g=mg\\\rho _{a} -\rho _{t}=\frac{n}{V} =\frac{340}{2950} =0.115kg/m^{3}$

$\rho _{t}=\rho _{a} -0.115=1.2-0.115=1.085kg/m^{3}$

The temperature is:

$T=\frac{P}{\rho _{t} R} =\frac{1.013x10^{5} }{1.085*287.05} =325.25K=52.25$°C