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3 years ago

An object is in motion if ___

Physics

2 answers:

iris [78.8K]3 years ago

3 0

Answer:

it changes position with respect to time

Explanation:

do you understand that?

8090 [49]3 years ago

3 0

Answer:

An object is in notion if its position change with time.

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You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 30.5 ∘ from the ground with a

Levart [38]

Answer:

5.39 m

Explanation:

From kinematics

$s=u_x t$ where t is time, s is distance and $u_x$ is initial speed in x direction

$u_x= 20.5cos 30.5=17.6634 m/s$

$u_y= 20.5 sin 30.5=10.40454 m/s$

Now 17.5=17.6634 t

$t=\frac {17.5}{17.6634}$ =0.99 s

Using the equation of kinematics

$h=u_y t- 0.5gt^{2}$

$h=10.40454\times 0.99^{2}-0.5\times 9.81\times 0.99^{2}$

h=5.39 m

5 0

3 years ago

A source emits sound with a frequency of 860 Hz. It is moving at 20.0 m/s toward a stationary reflecting wall. If the speed of s

Galina-37 [17]

Answer:

$f_o=860\ Hz$

Explanation:

Given:

original frequency of sound wave, $f=860\ Hz$

speed of the sound source, $v_s=20\ m.s^{-1}$

original speed of sound wave from the source, $s=343\ m.s^{-1}$

According to the Doppler's effect:

$\frac{f_s}{f_o} =\frac{s+v_s}{s-v_o}$

The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.

The velocity of the observer, $v_o=-20\ m.s^{-1}$

$\frac{860}{f_o} =\frac{s+20}{s-(-20)}$

$f_o=860\ Hz$

3 0

3 years ago

Read 2 more answers

1 A truck covers a distance of 580km in 7 hours - Calculate the velocity in km/hr

Digiron [165]

Answer:

82.86

Explanation:

to find velocity you displacement by time

3 0

3 years ago

Find the magnitude of the angular momentum of the second hand on a clock about an axis through the center of the clock face. Ass

Naddika [18.5K]

Answer:

L = 4.711 *10^{-6} kg m2/s

Explanation:

$i =\frac{ml^3}{3}$

$= \frac{0.00*.15^2}{3}$

=4.5*10^-5

angular velocity

$\omega = \frac{2\pi}{60}$

= 0.1047 rad/s

the angular momentum,

$L = I\omega$

$L = 4.5*10^{-5}* 0.1047 rad/s$

$L = 4.711 *10^{-6} kg m2/s$

3 0

3 years ago

Read 2 more answers

A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o

givi [52]

Answer:

$1.77\times 10^{-7}\ C/m^2$

0.000439077936334 m

Explanation:

q = Charge of electron = $1.6\times 10^{-19}\ C$

E = Electric field = $2\times 10^{4}\ N/C$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = $9.11\times 10^{-31}\ kg$

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

Electric flux is given by

$\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2$

The charge per unit area on the plates is $1.77\times 10^{-7}\ C/m^2$

Deflection is given by

$s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m$

The deflection is 0.000439077936334 m

7 0

3 years ago