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zmey [24]
3 years ago
5

How much work is done when an engine generates 400 Watts of power in 25 seconds?

Physics
2 answers:
IceJOKER [234]3 years ago
8 0

Answer:

10000 J or 10 KJ

Explanation:

power = workdone/time taken

400 = workdone/25

workdone = 400 * 25

=10000 J

Sunny_sXe [5.5K]3 years ago
6 0
Answer:

Power = work/time
Work = power x time
Work = 400 watts x 25 seconds
Work = 10,000 J
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An autotransformer is used to reduce the voltage of a 100-kilovolt amp, 480-volt secondary of an isolated type transformer, to s
tigry1 [53]

Answer:

42KVA

Explanation:

Given data

High Voltage (HV)= 480V

Low Voltage (LV)= 277V

Fo find

Size of transformer=?

Solution

To find the size of transformer here we use the co-ratio.The Co-ratio is given as:

Co-Ratio= (HV - LV)/HV

where

HV is High Voltage

LV is Low Voltage

Now put the values we get

Co- Ratio=(480-277)/480=.42

So the size of transformer is 42KVA

5 0
3 years ago
What is the velocity of a beam of electrons that goes undeflected when passing through perpendicular electric and magnetic field
goldenfox [79]
F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m
6 0
3 years ago
4. The Mariana trench is in the Pacific Ocean and has a depth of approximately 11,000 m. The density of seawater is approximatel
Alex73 [517]

Explanation:

It is known that relation between pressure and density is as follows.

            P = \rho gh

where,    P = pressure

     \rho = density

            g = acceleration due to gravity

            h = height

Putting the given values into the above formula as follows.

              P = \rho gh

                 = 1025 \times 9.8 \times 11000

                 = 110495000 Pa

Now, relation between pressure and force is as follows.

                P = \frac{F}{A}

or,            F = PA

                F = 110495000 \times \pi \times (0.1)^{2}

                   = 3.47 \times 10^{6} N

Thus, we can conclude that a force of 3.47 \times 10^{6} N can be  experienced at such depth.

3 0
3 years ago
An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below
grin007 [14]
<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

6 0
3 years ago
4. The result is that a(n)<br> electric current is induced<br> PLA
andrew11 [14]
The correct answer is:-

alternating.
3 0
3 years ago
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