The figure shows a velocity-versus-time graph for a particle moving along the x-axis. At t=0s, assume that x=0m. What is the par
ticle's position at t=3.0s?
1 answer:
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The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
<h3>What is magnetic force?</h3>Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:
where
The magnitude of the charge
The velocity of the charge
The magnitude of the magnetic field
The angle between the directions of v and B
By substituting the values we will get:
Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N
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