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kolezko [41]
3 years ago
9

Where does the suns rays strike earth most direcly and least directly

Physics
1 answer:
julia-pushkina [17]3 years ago
5 0
Most directly on equador and least directly at poluses
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How are sunspots related to prominences and solar flares?
solniwko [45]
<h2><u> Answer:</u></h2><h2><u /></h2>

The Sun is a star that experiences changes in its activity in a cycle of about 11 years, known as the solar cycle. During that time, the amount of sunspots on its surface may vary.

But first it is necessary to define what a sunspot is.

A <u>sunspot </u>is a region of the Sun that has a lower temperature than its surroundings, and with an intense magnetic activity. It consists of a dark central region, called <em>"umbra"</em>, surrounded by a lighter region<em>"penumbra"</em>.

Now, a solar protuberance or <u>prominence</u> is a large gaseous structure located on the surface of the Sun, often in a loop shape, which emerges from the surface of the Sun, the photosphere, and extends to reach the solar Corona. It is caused by disturbances in the Sun's magnetic field (hence it is<u> related to sunspots</u>) and, although most of the gas expelled returns to the surface, sometimes this can release particles that can reach the Earth.

In this context, a <u>solar flare</u> is a sudden, rapid and intense variation of brightness that is observed on the surface of the Sun due to an explosion of hot gases. It releases a large amount of energy in the form of electromagnetic radiation, energetic particles and mass in motion. These phenomena take place in active regions of the Sun, areas of strong magnetic field, and especially in sunspots with great magnetic complexity.

These eruptions are also known as Coronal Mass Ejections (CME), since they occur in the Sun's Corona layer; and can produce X-rays and gamma rays. However, <u>they are classified according to the peak of X-ray flow</u> by the letters A, B, C, M or X, where each letter (or class)  represents an increase in energy production 10 times greater than the previous one.

In summary:

<h2> When a sunspot is observed it is because in that region there was a coronal mass ejection, also known as a solar flare. This in turn is related to solar prominences. </h2>

7 0
3 years ago
Why does a bouncing ball rise to a lower height with each bounce? What energy conversion is taking place?
dsp73
<span>So we want to know why the does a bouncing ball rise to a lower height with each bounce. So lets say the ball is first on some height h. There it has potential energy Ep=m*g*h. Then as the ball starts falling to the ground the energy converts to kinetic energy Ek=(1/2)*m*v^2. When the ball falls to the ground, the kinetic energy transforms to elastic energy because the ball deforms as it hits the ground and some small quantity of heat. The heat goes to the air and to the ground so it gets removed from the system. So there is less energy in the system to be converted back to kinetic energy as the ball starts to rise in height again. Thats why the ball is not able to get bact to the same height as it started from. </span>
7 0
4 years ago
Prominences and sunspots are both:
Vadim26 [7]

Answer:

C. Influenced by the Sun's electromagnetic field

Explanation:

"Sunspots occur in pairs because each is one side of a loop of the Sun's magnetic field that reaches the Sun's surface. Solar prominences are the plasma loops that connect two sunspots."

8 0
3 years ago
a net force of 1,800 N is applied to a boat causing it to accelerate at 1.5 m/s^2. what is the mass of the boat?
Xelga [282]

Answer:

<h3>The answer is 1200 kg</h3>

Explanation:

The mass of an object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{1800}{1.5}  \\

We have the final answer as

<h3>1200 kg</h3>

Hope this helps you

7 0
3 years ago
Calculate the heat energy released when 13.3 g of liquid mercury at 25.00 C is converted to solid mercury at its melting point.C
dmitriy555 [2]

Answer:

-270.321012\ J

Explanation:

C_v = Heat capacity of Hg = 28 J/mol

\Delta T = Change in temperature = (234.32-(273.15+25))

\Delta H_{f} = Enthalpy of fusion = 2.29 kJ/mol

The number of moles is given by

n=13.3\times \dfrac{1}{200.59}\\\Rightarrow n=0.0663\ molHg

Heat is given by

Q_1=nC_v\Delta T\\\Rightarrow Q_1=0.0663\times 28\times (234.32-(273.15+25))\\\Rightarrow Q_1=-118.494012\ J

Heat released is given by

Q_2=-n\Delta H_{f}\\\Rightarrow Q_2=-0.0663\times 2.29\times 10^3\\\Rightarrow Q_2=-151.827\ J

Total heat is given by

Q=Q_1+Q_2\\\Rightarrow Q=-118.494012+(-151.827)\\\Rightarrow Q=-270.321012\ J

The total heat released is -270.321012\ J

4 0
3 years ago
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