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jok3333 [9.3K]
4 years ago
9

Tectonic plates can include

Physics
2 answers:
Umnica [9.8K]4 years ago
4 0
Both oceanic and continental crust.

I hope this helps!
NeTakaya4 years ago
3 0
<span><span>convergent, </span>divergent </span><span>and </span>transformants


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An LED is useful because when a current passes through it, it gives out light.

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How are nuclear reactions used to meet the world’s energy needs?
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Which of the following statements are true?
Virty [35]

Answer:

The true statements are;

a.The decrease in the amplitude of an oscillation caused by dissipative forces is called damping

b.An oscillation that is maintained by a driving force is called forced oscillation

Explanation:

To answer the question, we analyze each of the options as follows;

a.The decrease in the amplitude of an oscillation caused by dissipative forces is called damping.

The above statement is true as damped oscillation is one in which the amplitude is decreased by dissipative forces

b.An oscillation that is maintained by a driving force is called forced oscillation.

When a damped oscillator is allowed to oscillate by itself, it will stop eventually. However when a force is applied to maintain the oscillation the oscillation is then known as a forced oscillation

The above statement is true

c.In a mechanical system, the amplitude of an oscillation diminishes with time unless the lost mechanical energy is replaced.

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d.The increase in amplitude of an oscillation by a driving force is called forced oscillation.

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8 0
3 years ago
A rear window defroster consists of a long, flat wire bonded to the inside surface of the window. When current passes through th
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Answer:

\rho=1.8\times 10^{-8}\Omega.m

Explanation:

Given:

width of the wire, w=1.8\ mm=1.8\times 10^{-3}\ m

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length of the wire, l=12\ m

voltage across the wire, V=12\ V

current through the wire, I=12\ A

Now the net resistance of the wire:

using ohm's law

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R=\frac{12}{12}

R=1\ \Omega

We have the relation between the resistivity and the resistance as:

R=\rho.\frac{l}{a}

where:

a = cross sectional area of the wire

\rho = resistivity of the wire material

1=\rho\times \frac{12}{1.8\times 10^{-3}\times 1.2\times 10^{-4}}

\rho=1.8\times 10^{-8}\Omega.m

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