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3 years ago

13

What is the normal pH range of a Base?

2 answers:

daser333 [38]3 years ago

7 0

Answer:

The normal pH range if a base is more than 7

Explanation:

Basideally the pH range goes from 0-14 in which

Acidic range is :0-7

Neutral :7

Base : 7 - 14

Karolina [17]3 years ago

6 0

Answer:

7.35 - 7.45

Explanation:

The pH scale ranges from 0 (strongly acidic) to 14 (strongly basic or alkaline). A pH of 7.0, in the middle of this scale, is neutral. Blood is normally slightly basic, with a normal pH range of about 7.35 to 7.45. Usually, the body maintains the pH of blood close to 7.40.

Hope this helps

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Manganese (Mn) has many possible oxidation numbers (+2 and +4 are just two of these). Write the correct formulas and names for t

ohaa [14]

Answer:

Oxide of manganese, Potassium permanganate, Manganese bromide and manganese oxide.

Explanation:

1. Manganese dioxide

Its chemical formula is $MnO_2$ . It is +4 oxidation state. It is a black solid which is fairly stable.

2. Potassium permanganate

Its chemical formula is $KMnO_4$ . It is commonly used in the laboratories as oxidizing agent. They appear black in color.

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Its chemical formula is $MnBr_2$

4. Oxides of manganese

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4 years ago

A compound that is composed of only carbon and hydrogen contains 80.0% c and 20.0% h by mass. What is the empirical formula of t

gladu [14]

<u>Solution</u> : Emperical Formula = $CH_{3}$

Emperical Formula - A formula that gives the simplest whole number ratio of atom in a compound.

In the question percentages are given then assume that the total mass is 100grams so that the mass of each element is equal to the percentage given.

Given : 80.0g Carbon

20.0g Hydrogen

First convert the given masses into moles.

$80.0g\text{ C} \times \frac{1 g/mole \text{ C}}{12.0 g/mole \text{ C}}= 6.66\text{mole of C}$

$20.0g\text{ H} \times \frac{1 g/mole \text{ H}}{1 g/mole \text{ H}}= 20.0\text{mole of H}$

Value of each mole divided by the smallest number of moles and then round off.

Moles ratio of the element are

$\frac{6.66}{6.66}\text{mole of C}= 1$

$\frac{20.0}{6.66}\text{mole of C}= 3$

This is the mole ratio of the elements and is repersented by the subscript in the emperical formula.

Emperical Formula = $CH_{3}$

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Answer:

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Explanation:

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