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2 years ago

Which survey question is unbiased?

Mathematics

1 answer:

scoundrel [369]2 years ago

3 0

Answer:

Should be a dress code i hope this helps god bless you all

Step-by-step explanation:

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What is the surface area of the prism?

Vikentia [17]

B. 24 square meters. Length times width times height

5 0

3 years ago

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Which expression represents the sum (3z−11)+(6−6z) ?

Fudgin [204]

Answer: z = -5/-3

Step-by-step explanation:

(3z−11)+(6−6z)

3z - 11 + 6 - 6z

- 6z + 3z - 11 + 6

- 3z - 5

z = -5/-3

6 0

2 years ago

Is 5.2 greater than 60.3

yanalaym [24]

No, it is not. If you see closely, the number 5.2 is not 52. 60 is greater than 5.2.

4 0

3 years ago

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Hoping someone will help me out

pogonyaev

Answer:

It does not converge

Step-by-step explanation:

7 0

2 years ago

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A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled

klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}$

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

$\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5$

The standard deviation of the sample is calculated as:

$s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8$

Then, we can calculate the standard error of the mean as:

$\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5$

6 0

3 years ago