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Diano4ka-milaya [45]
3 years ago
12

I what process does a solid change directly into a vapor​

Chemistry
1 answer:
Marina86 [1]3 years ago
7 0

Answer:

solid change directly into a vapor in the process known simply as freezing

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Which of the following is not part of the proper protocol for using acids and bases?
Anni [7]

Answer:

B.Add acid to water,not water to acid

Explanation:

they should not be mixed

8 0
3 years ago
Which sample of co2 has a definite shape and definite volume
Kisachek [45]
The answer is Solid.

This is on account of the substances that develop a solid are packed in a settled, firmly pressed geometric plan.

4 0
3 years ago
A ground water tank has its height 2m. Calculate the pressure at its bottom when it is completely filled with water.​
Law Incorporation [45]

The pressure at the bottom : 19600 N/m²

<h3>Further explanation</h3>

Given

A ground water tank has its height 2m

Required

The pressure at its bottom

Solution

Hydrostatic pressure is the pressure caused by the weight of a liquid.  

The weight of a liquid is affected by the force of gravity.  

The hydrostatic pressure of a liquid can be formulated:  

\large{\boxed{\bold {P_h ~ = ~ \rho.g.h}}

Ph = hydrostatic pressure (N / m², Pa)  

ρ = density of liquid (kg / m³)  

g = acceleration due to gravity (m / s²)  

h = height / depth of liquid surface (m)  

ρ = density of water (kg / m³) = 1000

g = acceleration due to gravity = 9.8 m/ sec²

The pressure

\tt P=1000\times 9.8\times 2=19600~N/m^2

6 0
3 years ago
How can an invasive species like weeds affect crops on a farm?
Hoochie [10]

Answer:

E

Explanation:

All of the above

3 0
3 years ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
3 years ago
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