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Elena L [17]
2 years ago
14

Answer the following questions:

Chemistry
2 answers:
Y_Kistochka [10]2 years ago
8 0
Recrystallization is a technique used to purify chemicals, it's used for solid compounds most
Vera_Pavlovna [14]2 years ago
4 0

Answer:

fdfdgiukjgrguhjnfvthhhdqddwsvhjjj

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Which property is true for metals
san4es73 [151]

most metals conduct electricity and are very dull to the look. most metals are toxic if eaten and are hard.

aluminum is a type of metal they is softer than the opther and conducts eletricty like a boss.

nickel on the opther hand is also a metal but does not conduct a lot of electricy.

metals can be bent and others can break,

6 0
3 years ago
Read 2 more answers
A student calculates the density of an unknown metal sample to be 8.25 g/cm3
romanna [79]

Answer:

the answer is b

Explanation:

mass=198 divided by volume 24 gives you 8.25

4 0
3 years ago
ANYONE PLEASE HELP ME WITH MY CHEMISTRY HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW I HOPE Y’ALL CAN HELP ME:(
Delvig [45]
No lol ratio + bozo L
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2 years ago
which diagram best illustrates the ion-molecule attractions that occur wen the ions NaCl(s) are added to water
Viktor [21]

Answer:

answer is 1

Explanation:

4 0
3 years ago
3350 J of heat is required to raise the temperature of a sample of AlF3 from 250C to 800C. What is the mass of the sample?
Aleonysh [2.5K]

Answer:

  1. Look up the specific heat capacity of AlF₃
  2. Calculate ΔT
  3. Calculate the mass of AlF₃

Explanation:

The formula for for the heat (q) absorbed by an object is

 q = mCΔT, where

m = the mass of the sample

 C = the specific heat capacity of the sample. and

ΔT = the change in temperature

1. What you must do

  • Look up the specific heat capacity of AlF₃
  • Calculate ΔT
  • Calculate the mass of AlF₃

2. Sample calculation

For this example, I assume that the specific heat capacity of AlF₃ is 1.16 J·K⁻¹mol⁻¹ .

(a) Calculate ΔT  

\Delta T = T_{\text{f}} - T_{\text{i}} = 800 \, ^{\circ}\text{C} -250 \, ^{\circ}\text{C} = 550 \, ^{\circ}\text{C}

(b) Calculate m

\begin{array}{rcl}\text{3350 J} & = & m \times 1.16 \text{ J}\cdot\text{K}^{-1} \text{mol}^{-1}\times \text{550 K}\\3350 & = & m \times \text{638 g}^{-1}\\m & = &\dfrac{3350}{\text{638 g}^{-1}}\\\\ & = & \text{ 5.2 g}\\\end{array}\\

6 0
3 years ago
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