Answer:
The answer is 1.15m.
Since molality is defined as moles of solute divided by kg of solvent, we need to calculated the moles of H2SO4 and the mass of the solvent, which I presume is water.
We can find the number of H2SO4 moles by using its molarity
C=nV→nH2SO4=C⋅VH2SO4=6.00molesL⋅48.0⋅10−3L=0.288
Since water has a density of 1.00kgL, the mass of solvent is
m=ρ⋅Vwater=1.00kgL⋅0.250L=0.250 kg
Therefore, molality is
m=nmass.solvent=0.288moles0.250kg=1.15m
1) Ca-37, with a half-life of 181.1(10) ms.
Answer:
Redox
Explanation:
Reduction is gain of electrons
oxidation is loss of electrons
Answer:
Explanation:according to question:
. Nacl (aq) + AgNO3 (aq) --> AgCl
(s) + NaNO3 (aq).balanced.
