Answer:
28.9%
Explanation:
Let's consider the following balanced equation.
2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂
We can establish the following relations:
- The molar mass of Fe₂O₃ is 159.6 g/mol
- 1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
- 1 mole of Fe is in 1 mole of FeS₂
- The molar mass of Fe is 55.84 g/mol
The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:

The percent of Fe in 1.25 g of the ore is:

Answer:
1750L
Explanation:
Given
Initial Temperature = 25°C
Initial Pressure = 175 atm
Initial Volume = 10.0L
Final Temperature = 25°C
Final Pressure = 1 atm
Final Volume = ?
This question is an illustration of ideal gas law.
From the given parameters, the initial temperature and final temperature are the same; this implies that the system has a constant temperature.
As such, we'll make use of Boyle's Law to solve this;
Boyle's Law States that:
P₁V₁ = P₂V₂
Where P₁ and P₂ represent Initial and Final Pressure, respectively
While V₁ and V₂ represent Initial and final volume
The equation becomes
175 atm * 10L = 1 atm * V₂
1750 atm L = 1 atm * V₂
1750 L = V₂
Hence, the final volume that can be stored is 1750L
Answer:
water has several important physical properties. Most of the physical properties of water are quite atypical e.g molar mass is 18.0151grams per mol and melting point is 0.00 degree
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I believe the answer would be A. equal temperature
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Explanation:
1. photosynthesis
2. Nucleus. The nucleus is the largest and most significant living organelle of the cell. ... Hence it is called brain or control centre of the cell.
3.Cytoplasm
Cells require a thick jelly-like substance that holds organelles in place inside the cell. This substance is known. Cytoplasm. Turgor pressure can help plants move.
4.Chloroplasts absorbing solar energy for cellular activities.
5.cell membrane
6.a.cell wall
b.chloroplast
c.large vacuole