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3 years ago

Use pic for more info thx

Mathematics

2 answers:

kompoz [17]3 years ago

7 0

The answer is D, I had this question on a test before and I got it correct

SpyIntel [72]3 years ago

4 0

Answer:

D:86

Step-by-step explanation:

all three triangle sides always equal 180, so first you find the missing side. As you can see the angle you are finding is complementary to the missing side so its just the 180 minus the first answer.

You might be interested in

Differentiate the following by using "limit"

Nat2105 [25]

Answer:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \frac{ 1 }{ 2\sqrt{x } }$

Step-by-step explanation:

we want to differentiate the following by using limit:

$\displaystyle \frac{d}{dx} \sqrt{x}$

derivative definition by limit given by

$\rm \displaystyle \frac{d}{dx} = \lim _{\Delta x \to 0} \left( \frac{f(x + \Delta x) - f(x)}{ \Delta x} \right)$

given that,

f(x)=√x

so,

f(x+∆x)=√(x+∆x)

thus substitute:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ \sqrt{x + \Delta x}- \sqrt{x} }{ \Delta x} \right)$

multiply both the numerator and denominator by the conjugate of the numerator:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ \sqrt{x + \Delta x}- \sqrt{x} }{ \Delta x} \times \frac{ \sqrt{x + \Delta x} + \sqrt{x} }{\sqrt{x + \Delta x} + \sqrt{x}} \right)$

simplify which yields:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ (\sqrt{x + \Delta x}) ^{2} - x }{ \Delta x(\sqrt{x + \Delta x} + \sqrt{x})} \right)$

simplify square:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{ \Delta x \to 0} \left( \frac{ x + \Delta x - x }{ \Delta x(\sqrt{x + \Delta x} + \sqrt{x})} \right)$

collect like terms:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ \Delta x }{ \Delta x(\sqrt{x + \Delta x} + \sqrt{x})} \right)$

reduce fraction:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \lim _{\Delta x \to 0} \left( \frac{ 1 }{ (\sqrt{x + \Delta x} + \sqrt{x})} \right)$

get rid of ∆x as we are approaching its to 0

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \frac{ 1 }{ \sqrt{x } + \sqrt{x}}$

simplify addition:

$\rm \displaystyle \frac{d }{dx} \sqrt{x} = \frac{ 1 }{ 2\sqrt{x } }$

and we are done!

7 0

3 years ago

What is an equation of the line that passes through the point (-6,5) and is parallel

Tems11 [23]

Answer:

y=1/3x+7

Step-by-step explanation:

Hi there!

We're given the equation x-3y=21 and we want to find the equation of the line parallel to x-3y=21 that passes through (-6,5)

Parallel lines have the same slopes, but different y intercepts

So we need to find the slope of x-3y=21

To do that, we can convert x-3y=21 from standard form (ax+by=c where a, b, and c are integers) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept).

We'll need to isolate y onto one side

subtract x from both sides

-3y=-x+21

divide both sides by -3

y=1/3x-7

1/3 is in the place where m is, so 1/3 is the slope of the line

it's also the slope of the line parallel to x-3y=21

here's the equation of the line parallel to x-3y=21 so far:

y=1/3x+b

we need to find b

as the line passes through (-6,5), we can use it to solve for b

substitute -6 as x and 5 as y

5=1/3(-6)+b

multiply

5=-2+b

add 2 to both sides

7=b

Substitute 7 as b into the equation

y=1/3x+7

Hope this helps!

3 0

3 years ago

At the fair a pack of 25 ride tickets cost $43.75.<br><br> What is the price per ticket?

SCORPION-xisa [38]

You divide 25 by 43.75 and you will get 1.75

8 0

4 years ago

Simplify: 0.9(3÷2.25− 1 8 (1 2 3 + 1 9 ))− 4 7 ÷0.8

Finger [1]

Answer:

I'm not sure if it's right but I got -2455.15

Step-by-step explanation:

You would use PEMDAS,

( 129 + 19 ) = 148

-18 ( 148 ) = -2664

3/2.25 = 1.333333333

1.333333333 - 2664 = -2662.666667

0.9 ( -2662.666667 ) = -2396.4

-47/8 = -58.75

-2396.4 - 58.75 = <u>-2455.15</u>

4 0

3 years ago

The Jonas school district gives awards to its schools based on overall student attendance. The data for attendance are shown in

Evgesh-ka [11]

The most consistent attendance is the one that has less variability (it's more regular). Not necessarily the one with more students. So, the case with less variability is the one with less IQ, sigma or range (all three measure the dispersion of a distribution. IQ is more robust than sigma, and sigma more than the range, although in practice everyone uses sigma).

So, the answer to A) is the third High School: HS P

B) Here one looks at the central measurement: mean, median. This example is not super easy. HS N has the highest mean value, but HS P has the highest median. The median is more robust than the mean, since it is less affected by outliers. So HS P is a good candidate.

Finally, looking at the Low/High values, one can see that the high is the same: some day(s) when all students went and all HS have a maximum number of 180 students. However, the highest low is HS P.

So, I think HS P should also be awarded for the highest rate, since its median
is the highest and the lower number of students is the highest.

Median means 50% of the cases have values less than the median. Mean is an average.

3 0

3 years ago