Answer:
Explanation:
Since we are not given the mole fraction of ethanol and water; we will solve this theoretically.
Using Raoult's Law:
For water:
where 
of water = 12.5 mmHg
Then, the vapor pressure of water:
For ethanol:
and the of ethanol = 32.1 mmHg
Then, the vapor pressure of ethanol:
The total vapor pressure 
The total vapor pressure = 
Answer is: 55.125 grams <span>of propane must be burned.
</span>Balanced chemical reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
Make proportion: 1 mol(C₃H₈) : 2220 kJ = n(C₃H₈) : 2775kJ.
n(C₃H₈) = 2775 kJ·mol ÷ 2220 kJ.
n(C₃H₈) = 1.25 mol.
m(C₃H₈) = n(C₃H₈) · M(C₃H₈).
m(C₃H₈) = 1.25 mol · 44.1 g/mol.
m(C₃H₈) = 55.125 g.
n - amount of substance.
Answer:
The correct answer is the final pair: C4H10 and C2H5
Explanation:
Took the test and it was right. :)
Answer:
The correct option is A
Explanation:
An independent variable is <u>a variable that is intentionally altered (directly or indirectly) and is not dependent on another variable</u> in the course of an experiment. Unlike the independent variable, the dependent variable depends or is presumed to depend on the altered independent variables.
From the explanation above, it can be deduced that the concentration of the catalase is the independent variable as it was intentionally altered (by using different concentrations) in the course of the experiment. The amount of oxygen given off is the dependent variable here
