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Elis [28]
3 years ago
15

55.845 nearest tenth

Chemistry
2 answers:
Oksanka [162]3 years ago
8 0

Answer:

55.8

Explanation:

saveliy_v [14]3 years ago
6 0

Answer: 55.8

Explanation:

there is more possible answers

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Sergio039 [100]

Answer:

7

8

9

10.

better check book pages for this kinda answer.

8 0
3 years ago
Which of the three variables that apply to the equal amounts of gases are directly proportional? Which are inversely proportiona
levacccp [35]
<span>when temperature varies: 
volume & temperature vary directly @ constant pressure,... Charles' law 
pressure & temperature vary directly @ constant volume,... Gay-Lussac's law 

when temp is consatnt: 
Pressure & volume vary inversely , ...Boyle's law

Hope This Helped! :3</span>
8 0
3 years ago
Read 2 more answers
Consider the type of plant in which edible spoons and other disposable spoons would be produced. What systems would have to be i
Amiraneli [1.4K]
The plants are on the edible spoons
4 0
3 years ago
The natural gas in a storage reservoir, under a pressure of 1.00 atmosphere, has a volume of 2.74 × 109 L at 20.0°C. The tempera
Soloha48 [4]

Answer : The final volume of gas will be, 2.36\times 10^9L

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{V_2}=\frac{T_1}{T_2}

where,

V_1 = initial volume of gas = 2.74\times 10^9L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 20.0^oC=273+20.0=293K

T_2 = final temperature of gas = -20.0^oC=273+(-20.0)=253K

Now put all the given values in the above formula, we get the final volume of the gas.

\frac{2.74\times 10^9L}{V_2}=\frac{293K}{253K}

V_2=2.36\times 10^9L

Therefore, the final volume of gas will be, 2.36\times 10^9L

8 0
3 years ago
A sample of air occupies 4.40 L when the pressure is 2.60 atm.
julia-pushkina [17]

Explanation:

Given that,

Initial volume, V₁ = 4.40 L

Initial pressure, P₁ = 2.6 atm

(a) Final pressure, P₂ = 6.2 atm

As per the relation,

P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{2.6\times 4.4}{6.2}\\\\V_2=1.84\ L

(b) Again using the above relation,

P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{2.6\times 4.4}{0.0290 }\\\\P_2=394.48\ atm

Hence, this is the required ssolution.

8 0
3 years ago
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