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Elis [28]
3 years ago
15

55.845 nearest tenth

Chemistry
2 answers:
Oksanka [162]3 years ago
8 0

Answer:

55.8

Explanation:

saveliy_v [14]3 years ago
6 0

Answer: 55.8

Explanation:

there is more possible answers

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the anwser would be B obtain energy

Explanation:

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The atomic bomb detonated in 1945 produced an explosion equivalent to 18,600 tons of TNT from 5 kg of _____.
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Vladimir79 [104]

Answers:

1. 3-ethyl-3-methylheptane; 2. 2,2,3,3-tetramethylpentane; 3. hexa-2,4-diene.

Explanation:

<em>Structure 1 </em>

  1. Identify and name the longest continuous chain of carbon atoms (the main chain has 7 C; ∴ base name = heptane).
  2. Identify and name all the substituents [a 1C substituent (methyl) and a 2C substituent (methyl).
  3. Number the main chain from the end closest to a substituent.
  4. Identify the substituents by the number of the C atom on the main chain. Use hyphens between letters and numbers (3-methyl, 3-ethyl).
  5. Put the names of the substituents in alphabetical order in front of the base name with no spaces (3-ethyl-3-methylheptane)

<em>Structure 2</em>

  1. 5C. Base name = pentane
  2. Four methyl groups.
  3. Number from the left-hand end.
  4. If there is more than one substituent of the same type, identify each substituent by its locating number and use a multiplying prefix to show the number of each substituent. Use commas between numbers (2,2,3,3-tetramethyl).
  5. The name is 2,2,3,3-tetramethylpentane.

<em>Structure 3 </em>

  1. Identify and name the longest continuous chain of carbon atoms that passes through as many double bonds as possible. Drop the <em>-ne</em> ending of the alkane to get the root name <em>hexa-</em>.
  2. (No substituents).
  3. Number the main chain from the end closest to a double bond.
  4. If there is more than one double bond use a multiplying prefix to indicate the number of double bonds (two double bonds = diene) and use the smaller of the two numbers of the C=C atoms as the double bond locators (2,4-diene)
  5. Put the functional group name at the end of the root name (hexa-2,4-diene).

<em>Note</em>: The name 2,4-hexadiene is <em>acceptable</em>, but the <em>Preferred IUPAC Name</em> puts the locating numbers as close as possible in front of the groups they locate.

7 0
3 years ago
Each student in a class placed a 2.00 g sample of a mixture of Cu and Al in a beaker and placed the beaker in a fume hood. The s
Aleks [24]

Answer:

Percentage mass of copper in the sample = 32%

Explanation:

Equation of the reaction producing Cu(NO₃) is given below:

Cu(s)+ 4HNO₃(aq) ---> Cu(NO₃)(aq) + 2NO₂(g) + 2H₂O(l)

From the equation of reaction, 1 mole of Cu(NO₃) is produced from 1 mole of copper. Therefore, 0.010 moles of Cu(NO₃) will be produced from 0.010 mole of copper.

Molar mass of copper = 64 g/mol

mass of copper = number of moles * molar mass

mass of copper = 0.01 mol * 64 g/mol = 0.64 g

Percentage by mass of copper in the 2.00 g sample = (0.64/2.00) * 100%

Percentage mass of copper in the sample = 32%

3 0
3 years ago
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