1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marina CMI [18]
3 years ago
12

Catalase is an enzyme that speeds up the breakdown of hydrogen peroxide in cells. During this reaction oxygen is given off. A sc

ientist designs an experiment to determine how much oxygen is given off when varying concentrations of catalase are used. Identify the independent variable A the concentration of the catalase B the result of the reaction C Type of proxide D the shape of the container
Chemistry
1 answer:
Softa [21]3 years ago
6 0

Answer:

The correct option is A

Explanation:

An independent variable is <u>a variable that is intentionally altered (directly or indirectly) and is not dependent on another variable</u> in the course of an experiment. Unlike the independent variable, the dependent variable depends or is presumed to depend on the altered independent variables.

From the explanation above, it can be deduced that the concentration of the catalase is the independent variable as it was intentionally altered (by using different concentrations) in the course of the experiment. The amount of oxygen given off is the dependent variable here

You might be interested in
There are diffrent types of cells for every job in your body. How do we refer to those cells that develop differently?
kotykmax [81]

<u>Answer:</u>

Those cells that develop differently are referred  to Specialised Cells.

<u> </u><u>Explanation:</u>

Specialised cells are the one that is assigned to perform a specific role. Every specialised cell in the body is assigned to do their own job. The special features in them help them to perform their functions effectively.

Examples of specialised cells are- red blood cells (they are responsible to carry oxygen in the body), nerve cells (specialises in transmitting electrical signals) and muscle cells (brings body parts together).  

3 0
3 years ago
Which of the following expressions best represents a second order rate law?
Ksivusya [100]
I think the correct answer would be C. The expression that would best represent a second order rate law would be r =k[X][Y]. Reaction with this rate law are those that depend on the concentration of two first order reactants or a second order reactant.
8 0
3 years ago
Each molecule of table sugar, C12H22O11, contains
Delicious77 [7]
D, because C12 means there's 12 atoms of carbon. 
3 0
3 years ago
Read 2 more answers
Sound travels faster in high temperatures.:<br> True<br> False
fredd [130]
Answer:

False

Explanation: sound travels fastest through solids slowest through liquids.
5 0
3 years ago
Read 2 more answers
The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat
Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

 Half life of lipase t_{1/2} = 8 min x 60 s/min

                                       = 480 s

Rate constant for first order reaction is as follows.

         k_{d} = \frac{0.6932}{480}

                        = 1.44 \times 10^{-3}s^{-1}&#10;

Initial fat concentration S_{o} = 45 mol/m^{3}

                                                = 45 mmol/L

Rate of hydrolysis V_m_{o} = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = S_{o} (1 - X)

                                      = 45 (1 - 0.80)

                                      = 9 mol/m^{3}

or,                                  = 9 mmol/L

It is given that K_{m} = 5mmol/L

Therefore, time taken will be calculated as follows.

                    t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]

Now, putting the given values into the above formula as follows.

            t = -\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]  

             = -\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s&#10;}{K_{M} ln (\frac{45 mmol/L&#10;}{9 mmol/L&#10;}) + (45 mmol/L - 9 mmol/L&#10;)]

              = 1642.83 s \times \frac{1 min}{60 sec}

              = 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0
3 years ago
Other questions:
  • Describe a homogeneous mixture
    10·2 answers
  • 150 lb of NaCl are initially dissolved in 500 gal of a NaCl solution in a container. Water is continuously added to the containe
    12·1 answer
  • A student working in the laboratory prepared the following reactants: 5 mL of 0.007M Cd2+(aq) 10 mL of 0.008M SCN-(aq) 10 mL of
    6·1 answer
  • When a student mixes 50 mL of 1.0 M HCl and 50 mL of 1.0 M NaOH in a coffee-cup calorimeter, the temperature of the resultant so
    14·2 answers
  • What is the coefficient of the acid that produces AlCl3 in the reaction mixing Al(OH)3 and HCl after the equation has been balan
    15·1 answer
  • What Kelvin temperature is the same as -13° Celsius?
    8·1 answer
  • The density of cadmium is 8.65 g/mL, what is the volume of a 33.4 g object made of pure cadmium?
    9·1 answer
  • Deep sea divers can experience the bends due to an increased amount of nitrogen in the blood
    9·1 answer
  • Can you solve this. <br>I need it. <br>:) :):)​
    15·1 answer
  • If liquid carbon disulfide reacts with 450 mL of oxygen to produce the gases carbon dioxide and sulfur dioxide, what volume of e
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!