-6 3/5 - (-7 4/15) + 2 1/5

Find the standard deviation for the given data. Round your answer to one more decimal place than the original data. To get the b

ale4655 [162]

Answer:

$122.1

Step-by-step explanation:

We are given the following data in the question

$124, $256 , $118, $441, $122, $335, $340, $191

Step 1

Find the mean

Mean = Sum of Terms / Number of Terms

Number of Terms = 8

Mean = ($124 + $256 + $118 + $441 + $122 + $335 + $340 + $191 )/ 8

Mean = $1927/8

= $240.875

Approximately to 1 decimal place

$240.9

Step 2

Standard deviation formula

S = √( x - μ)²/ N - 1),

N = Number of terms

μ = Mean

S = √[($124 - $240.9)² + ($256 - $240.9)² + ($118 - $240.9)² + ($441 - $240.9)² + ($122 - $240.9)² + ($335 - $240.9)² + ($340 - $240.9)²+ ($191 -$240.9)²/ 8 - 1]

S = $122.0895

Approximately to 1 decimal place

S = $122.1

Therefore, the standard deviation for the given data is $122.1

7 0

4 years ago

I REALLY NEED HELP PLEASEE!!!

charle [14.2K]

Answer:

Hard for me sry

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

As

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

so

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$