Answer:
2
Explanation:To find the solution we must first make the transformations to international units,
In this way:
Inches of length (L) to feet =
So we can identify the area by hour:
Once the area is identified, we now identify the number of passes required,
Passes required = Area x number of passes
We transform speed to international units
So we can identify the covered area
where
m = drum widht
p = efficiency
In this way we obtain the number of rollers given by:
No. of Rollers = Passes required / covered area
No of rollers = 48136/40269
No of rollers = 1.19, that is, 2
Read more on Brainly.com - brainly.com/question/13686900#readmore.
Answer:
a) it is periodic
N = (20/3)k = 20 { for K =3}
b) it is Non-Periodic.
N = ∞
c) x(n) is periodic
N = LCM ( 5, 20 )
Explanation:
We know that In Discrete time system, complex exponentials and sinusoidal signals are periodic only when ( 2π/w₀) ratio is a rational number.
then the period of the signal is given as
N = ( 2π/w₀)K
k is least integer for which N is also integer
Now, if x(n) = x1(n) + x2(n) and if x1(n) and x2(n) are periodic then x(n) will also be periodic; given N = LCM of N1 and N2
now
a) cos(2π(0.15)n)
w₀ = 2π(0.15)
Now, 2π/w₀ = 2π/2π(0.15) = 1/(0.15) = 1×20 / ( 0.15×20) = 20/3
so, it is periodic
N = (20/3)k = 20 { for K =3}
b) cos(2n);
w₀ = 2
Now, 2π/w₀ = 2π/2) = π
so, it is Non-Periodic.
N = ∞
c) cos(π0.3n) + cos(π0.4n)
x(n) = x1(n) + x2(n)
x1(n) = cos(π0.3n)
x2(n) = cos(π0.4n)
so
w₀ = π0.3
2π/w₀ = 2π/π0.3 = 2/0.3 = ( 2×10)/(0.3×10) = 20/3
∴ N1 = 20
AND
w₀ = π0.4
2π/w₀ = 2π/π0. = 2/0.4 = ( 2×10)/(0.4×10) = 20/4 = 5
∴ N² = 5
so, x(n) is periodic
N = LCM ( 5, 20 )
Preliminary studies found that skin friction drag accounts for between 20 to 40% of overall drag.
<h3>Explain about the skin friction?</h3>
Aerodynamic drag, which is a resistive force applied to an object moving in a fluid, includes skin friction drag.
The viscosity of a fluid as it passes across a surface is what creates skin friction. Its size is determined by the fluid's viscosity, the amount of wetted (or total) surface area in contact with it, and the degree of roughness of the surface.
Skin friction is important because it plays a role in the erosion of sediment particles from the water-bed boundary condition. Regarding the vertical mixing of the sediment over the water depth, form drag-related turbulence (separation-induced eddies, etc.) is significant.
To learn more about skin friction refer to:
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Answer:
a) omax=125 MPa
omin=75 MPa
b) Temperature = 1289.6°F
Explanation:
a) The mean stress is:
omax+omin=200 MPa
stress amplitude=50 MPa
omax-omin=50MPa
2omax=250 MPa
omax=125 MPa
omin=75 MPa
b) For copper, the creep is important at 0.65 of the melting point, thus:
Temperature = 0.65*1984°F=1289.6°F
Answer:
a) see attachment
b) A= m0m1+ m1m2+ m0m2
see attachment for K-map
c) see attachment
Explanation:
a) see attachment for truth table
b) see attachment for k-map
A= m0m1+ m1m2+ m0m2
c) see attachment for gate level circuit