Although studs are sometimes spaced 24" O.C. in residential structures, a spacing of_____ O.C. is more commonly used.
1 answer:
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Answer:
<em>a) 50 J/kg</em>
<em>b) 721 67 KW</em>
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Explanation:
The velocity of the wind v = 10 m/s
diameter of the blades d = 70 m
efficiency of the turbine η = 30%
density of air ρ = 1.25 kg/m^3
The area of the blade A =
A = = 3848.95 m^2
The mechanical energy air per unit mass is gives as
e = =
= <em>50 J/kg</em>
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Theoretical Power of the turbine P = ρAve
where
ρ is the density of air
A is the area of the blade
v is the velocity of the wind
e is the energy per unit mass
substituting values, we have
P = 1.25 x 3848.95 x 10 x 50 = 2405593.75 W
Actual power = ηP
where η is the efficiency of the turbine
P is the theoretical power of the turbine
Actual power = 0.3 x 2405593.75 = 721678.1 W
==> <em>721 67 KW</em>
Answer:
Note that Air requires lesser work
Explanation:
Calculate for general work done
SInce Gas constant 'R' for: Neon = 0.4119KJ/kg.k , and Air = 0.287 kJ/kg·K
Calculate for work done of NEON
Calculate for work done of Air
See solution attached.
