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Liula [17]
2 years ago
12

The purpose of a diamond-shaped yellow sign with black markings is to.

Engineering
1 answer:
Anit [1.1K]2 years ago
4 0

Answer:

it is to warn you about something like a dead end, or maybe where you should slow down because there might be people crossing ahead.

Explanation:

look at the signs i provided, all of them warn you about something.

Ex: railroad tracks, there might be a train passing, a winding road, so you don't go off road and crash, etc.

You might be interested in
Describe five tools used in suspension system service and repair
dmitriy555 [2]

Answer:

Explanation:

You'll still need wrenches, sockets and screwdrivers, but there are other things that it may be necessary to buy to complete the work.

Spring Compressor. One part of suspension repair is replacing coil springs.  

Hydraulic Puller. -Hydraulic pullers are used to remove shaft-fitted parts (bearings or couplings). Pullers use a controlled hydraulic force in an effective way and can quickly separate (especially compared to the manual alternative) the parts.

CV Boot Tool. he CV Boot is a ribbed, rubber flexible boot that keeps water and dirt out of the joint and the special grease inside the joint.

Torque Wrench. .A torque wrench is a tool used to apply a specific torque to a fastener such as a nut, bolt, or lag screw. ... A torque wrench is used where the tightness of screws and bolts is crucial.

Ball Joint Separator. This tool is used to separate the ball joint from the spindle support arm. It works on many domestic and import front wheel drive vehicles and is adjustable up to 2" for different size ball joints.

Strut Nuts.  

Tie Rod Puller.

etc....

7 0
3 years ago
What is the weight density of a 2.24 in diameter titanium sphere that weights 0.82 lb?
nasty-shy [4]

Answer:

0.14\ lb/in^{3}

Explanation:

Density is defined as mass ler unit volume, expressed as

\rho=\frac {m}{v}

Where m is mass, \rho is density and v is the volume. For a sphere, volume is given as

v=\frac {4\pi r^{3}}{3}

Replacing this into the formula of density then

\rho=\frac {m}{\frac {4\pi r^{3}}{3}}

Given diameter of 2.24 in then the radius is 1.12 in. Substituting 0.82 lb for m then

\rho=\frac {0.82}{\frac {4\pi 1.12^{3}}{3}}=0.13932044952427\approx 0.14 lb/in^{3}

4 0
4 years ago
Output all combinations of character variables a, b, and c. If a = 'x', b = 'y', and c = 'z', then the output is: xyz xzy yxz yz
gladu [14]

Answer & Explanation:

//written in java

public class Main {

   public static void main(String[] args) {

       //declare a char variable for a, b, c

       char a;

       char b;

       char c;

       //assign a b and c

       //a b and c can be replaced for with  

       // '#', '$', '%', then with '1', '2', '3'

       // for further testing

       a = 'x';

       b = 'y';

       c = 'z';

       //output for all possible combination for a, b, c.

       System.out.println("" + a + b + c + " " + a + c + b + " " + b + a + c +

               " " + b + c + a + " " + c + a + b + " " + c + b + a);

   }

}

7 0
4 years ago
Niobium has a BCC crystal structure, an atomic radius of 0.143 nm and an atomic weight of 92.91 g/mol. Calculate the theoretical
Olin [163]

Answer:

The theoretical density for Niobium is 1.87 g/cm^3.

Explanation:

Formula used :  

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density  of the unit cell

Z = number of atom in unit cell

M = atomic mass

(N_{A}) = Avogadro's number  

a = edge length of unit cell

We have :

Z = 2 (BCC)

M = 92.91 g/mol ( Niobium)

Atomic radius for niobium = r = 0.143 nm

Edge length of the unit cell = a

r = 0.866 a (BCC unit cell)

a=\frac{0.143 nm}{0.866}=0.165 nm=0.165 \times 10^{-7} cm

1 nm = 10^{-7} cm

On substituting all the given values , we will get the value of 'a'.

\rho=\frac{2\times 92.91}{6.022\times 10^{23} mol^{-1}\times (0.165 \times 10^{-7} cm)^{3}}

\rho =1.87 g/cm^3

The theoretical density for Niobium is 1.87 g/cm^3.

6 0
3 years ago
Read 2 more answers
Write a statement that increases numPeople by 5. Ex: If numPeople is initially 10, the output is: There are 15 people.
BartSMP [9]

Answer:

import java.util.Scanner;

public class AssigningNumberToVariable {

public static void main (String [] args) {

int numPeople;

int numPeople_inc;

numPeople = 10;

/* solution */

numPeople_inc=numPeople+5;

System.out.print("There are ");

System.out.print(numPeople_inc);

System.out.println(" people.");

}

}

Explanation:

1. Declare a new variable called: numPeople_inc

2. Add 5 each time: numPeople_inc=numPeople+5;

3. Print the answer:  numPeople_inc=numPeople+5;

Optional, just write the line in the place where says: " your solutions goes here":

numPeople = numPeople+5;

8 0
3 years ago
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