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sweet [91]
3 years ago
8

Write an equation of the line passing through point (7,3) that is parallel to line 4x-7y=9

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

y= 4/7x -1  

Step-by-step explanation:

solve for y first in 4x-7y=9, which becomes y = 4/7x - 9/7, then since its a parallel line the slope stays the same which is 4/7. Then plug into this equation: y =mx+b, in which you plug in the point for the x and y values and you plug in the slope for m, so the equation becomes, 3 = (7)(4/7) + b and now solve for b in which b = -1 and now write the equation using all the corresponding things so the equation becomes: y= 4/7x -1  

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Answer:

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Step-by-step explanation:

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3 years ago
Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - y_{1} = m( x-x_{1} )

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

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</span>
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