Answer:
The temperature after ignition is 7859.565 K
Explanation:
Here we have
Energy released = 1970 J
Volume of gas = 47.9 cm³ = 0.0000479 m³
Pressure of gas = 1.18 × 10⁶ Pa
Temperature of he gas = 325 K
From P·V = n·R·T
Therefore, n = PV/(RT) = (0.0000479 × 1.18 × 10⁶)/(8.3145× 325) = 2.09 × 10⁻² moles
For an ideal mono-atomic gas, the mono-atomic gas, the molar heat capacity at constant volume is given as
= 3/2 R ≈ 12.5 J K−1 mol⁻¹
Therefore we have
Heat released, ΔH = 1970 J = n × ×(T₂ - T₁) = 2.09 × 10⁻² × 12.5×(T₂ -325)
T₂ = (1970 J)/(2.09 × 10⁻² × 12.5) + 325
= 7534.565 +325 = 7859.565 K
The temperature after ignition = 7859.565 K.
Answer:
is the height of the TV screen.
Explanation:
Given:
diagonal of TV screen,
width of TV scree,
As we know that the TV screen is rectangular in shape so including its height and with along with the diagonal forms a right angled triangle in which the diagonal is the hypotenuse of the triangle formed so.
is the height of the TV screen.
Answer:
3.True. The magnitude of momentum is the same
Explanation:
Let's propose the solution of the problem
The initial moment is
p₀ = m v
The final moment
= m (-v)
p₀ = -
Now we can review the claims
1. False. We see that the moment module is the same, but its direction changes
2. False. The impulse is a vector
3.True. The magnitude of momentum is the same