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masya89 [10]
2 years ago
7

HELP ASAP PLS ILL GIVE YOU BRAINLIEST

Physics
2 answers:
lys-0071 [83]2 years ago
8 0

Answer:

chinese

Explanation:

Reil [10]2 years ago
7 0

Answer:

B chinese

hope this helps you

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A positive point charge (q = +5.45 x 10-8 C) is surrounded by an equipotential surface A, which has a radius of rA = 1.49 m. A p
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Answer:

r_{B} = 3.34\ m

Solution:

As per the question:

Point charge, q = 5.45\times 10^{- 8}\ C

Test charge, q_{o} = 4.96\times 10^{- 11}\ C

Work done by the electric force, W_{AB} = - 9.05\times 10^{- 9}\ J

Now,

We know that the electric potential at a point is given by:

V = \frac{kqq'}{r}

where

r = separation distance between the charges.

Also,

The work done by the electric force i moving a test charge from point A to B in an electric field:

W_{AB} = kqq_{o}(\frac{1}{r_{B} - \frac{1}{r_{A}}}

- 9.05\times 10^{- 9} = 9\times 10^{9}\times 5.45\times 10^{- 8}\times 4.96\times 10^{- 11}(\frac{1}{r_{B}} - \frac{1}{1.49}}

- 0.3719 = (\frac{1}{r_{B}} - 0.67}

r_{B} = \frac{1}{0.299} = 3.34\ m

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3 years ago
These plans are an accompaniment to mechanical lifting devices in reducing on-the-job injuries. they address specific patient ne
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A single polarizer will stop _____ of the incoming light.
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A single polarizer will stop 50% of the incoming light.
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5. How will you separate water from petrol?
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Tom is throwing an baseball at an aluminum can,
pishuonlain [190]

Answer:

The question relates to the conservation of energy principle, the conservation of the linear momentum, and Newton's Laws of motion

Part A

1) Tom throwing a baseball at a can

The initial velocity of the baseball = v₂

The initial kinetic energy of the baseball, K.E.₂ = (1/2)·m₂·v₂²

∴ The final kinetic energy of the baseball, K.E.₂' = (1/2)·m₂·v₂'² < (1/2)·m₂·v₂²

Therefore, the energy of the ball before the collision is lesser than the energy of the ball after the collision

2) The evidence that would likely support the claim is that the baseball's height above the ground reduces rapidly immediately after the collision which is due to the reduced velocity, and therefore, the reduced (kinetic) energy

The final velocity of the baseball v₂' < v₂

Part B

1) The argument

The initial velocity of the can = v₁ = 0 (The can is initially  at rest)

The initial kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² = 0

The final velocity of the can v₁' > v₁ = 0

∴ The final kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² > 0

Given that the velocity of the can increases from zero to a positive value after collision with the baseball, the kinetic energy of the can is increased from zero before the collision to a positive value after the collision

2) An evidence in support of the argument is the motion of the can which was initially at rest which is an indication of increase in energy podded by the can

Explanation:

8 0
2 years ago
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