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Setler79 [48]
3 years ago
9

Tin shear have longer handles than than the scissor used to cut cloth give reason​

Physics
1 answer:
natka813 [3]3 years ago
8 0

Answer:

For scissor, small movement at effort(at handle) should make long movement of load arm , so that it can cut longer lengths of cloth/paper. Hence blades are longer than handle.so its handle(load arm) is made longer than its blades.

Explanation:

Hope this helped Mark BRAINLEST!!

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Railroad cars are loosely coupled so that there is a noticeable time delay from the time the first and last car is moved from re
olga nikolaevna [1]

Answer:

Without this slack, a locomotive might simply sit still and spin its wheels. The loose coupling enables a longer time for the entire train to gain momentum, requiring less force of the locomotive wheels against the track. In this way, the overall required impulse is broken into a series of smaller impulses. (This loose coupling can be very important for braking as well).

Explanation:

8 0
3 years ago
A train brakes from 25 m/s to rest in 30 sec. What is its deceleration?
givi [52]

Answer:

a= -0.83m\s^2

Explanation:

a = v \ t

a = -25 \ 30 = -0.833 m\s^2

the object is slowing down 0.83 meter every second

8 0
3 years ago
G s w d v b k x s r only for freinds <br> Have a pretty heart
tamaranim1 [39]

Answer:

what do you mean

Explanation:

6 0
1 year ago
A 7800 W lift took 10 seconds to move a 5000 N weight. How far did the lift move this weight?
Eduardwww [97]

Answer:

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7 0
3 years ago
QUESTION 3 ( MARKS]
horrorfan [7]

Answer:

392 N

Explanation:

Draw a free body diagram of the rod.  There are four forces acting on the rod:

At the wall, you have horizontal and vertical reaction forces, Rx and Ry.

At the other end of the rod (point X), you have the weight of the sign pointing down, mg.

Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.

Sum of the moments at the wall:

∑τ = Iα

(T sin θ) L − (mg) L = 0

T sin θ − mg = 0

T = mg / sin θ

Given m = 20 kg and θ = 30.0°:

T = (20 kg) (9.8 m/s²) / (sin 30.0°)

T = 392 N

7 0
3 years ago
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