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Varvara68 [4.7K]
3 years ago
5

Please help me with this question

Mathematics
1 answer:
FrozenT [24]3 years ago
8 0
1/2 divided by 2 is 1
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There is 6 1/8ths in 3/4ths
4 0
3 years ago
Read 2 more answers
Is this right idk but i need work fir it
bija089 [108]

Answer:

The answer is C 5/4

Step-by-step explanation:

When lines are parallel and you know there is a scalar factor, make the ratio by putting the original over the dilation 15:12 or 15/12 this is the ratio and after you need to reduce by dividing by the greatest common factor. 15 and 12's GCF is 3 so (15/3)/(12/3) = 5/4.

7 0
3 years ago
I need some help please :)​
const2013 [10]
ADC = DAB
CAD = BDA
Answer: DAB, BDA
8 0
3 years ago
At 5 seconds, an object's velocity is 9 meters per second. At 8 seconds, the object's velocity is 25 meters per second. Assuming
RideAnS [48]

Acceleration  =  (change in speed) / (time for the change) .

Change in speed = (25 m/s - 9 m/s) =  16 m/s

Time for the change = (8 sec  -  5 sec)  =  3 seconds

Acceleration  =  (change in speed) / (time for the change)

                       =                 (16 m/s)  /  (3 sec) 

                       =                          (5 and 1/3)  m/s²  .

(rounded to the nearest hundredth ...  5.33 m/s² . )
7 0
3 years ago
Click here please. The problems are in picture format
padilas [110]

First picture:

You got the first two right (good job!), so I'll just tackle the third one. If you have to compute f(x-4), it means that you have to substitute x-4 in place of x. Differently from the first two points, this will generate a new function, rather than a specific value:

f(x) = \sqrt{x+4}+2 \implies f(x-4) = \sqrt{(x-4)+4}+2 = \sqrt{x}+2

Second picture:

Given the point (x,y) highlighted in the picture, you can deduce that the base is 2x units long (since it spans from (-x,0) to (x,0)) and the height is y units long (because it spans from (x,0) to (x,y)). So, the area of the rectangle is the multiplication between base and height:

A = 2xy

But we know that y=f(x)=\sqrt{36-x^2}, so we have

A = 2x\sqrt{36-x^2}

The domain of this function is given by the domain of the square root: we want its argument to be non, negative, so we have

36-x^2 \geq 0 \iff x^2 \leq 36 \iff -6 \leq x \leq 6

But since the problem is symmetric, the answer is

0 \leq x \leq 6

You can only see the answer 0 < x < 6 because, if you choose x=0 or x=6, the rectangle degenerates to a segment, and your exercise doesn't like this scenario, apparently

4 0
4 years ago
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