<span>the atomic mass of nitrogen is 14. There is 1 nitrogen atom in the molecule so the percentage of N is :
14/35 x100% = 40%</span>
Answer:
1 temperature 2 weather 3 the stratosphere 4 decreases 5 increases
Explanation:
<h3>The density of H₂ = 0.033 g/L</h3><h3>Further explanation</h3>
In general, the gas equation can be written
![\large {\boxed {\bold {PV = nRT}}}](https://tex.z-dn.net/?f=%5Clarge%20%7B%5Cboxed%20%7B%5Cbold%20%7BPV%20%3D%20nRT%7D%7D%7D)
where
P = pressure, atm , N/m²
V = volume, liter
n = number of moles
R = gas constant = 0.082 l.atm / mol K (P= atm, v= liter),or 8,314 J/mol K (P=Pa or N/m², v= m³)
T = temperature, Kelvin
n = N / No
n = mole
No = Avogadro number (6.02.10²³)
n = m / MW
m = mass
MW = molecular weight
For density , can be formulated :
![\tt \rho=\dfrac{P\times MW}{R\times T}](https://tex.z-dn.net/?f=%5Ctt%20%5Crho%3D%5Cdfrac%7BP%5Ctimes%20MW%7D%7BR%5Ctimes%20T%7D)
P = 327 mmHg = 0,430263 atm
R = 0.082 L.atm / mol K
T = 48 ºC = 321.15 K
MW of H₂ = 2.015 g/mol
The density :
![\rho=\dfrac{0,430263\times 2.015 }{0.082\times 321.15}\\\\\rho=0.033~g/L](https://tex.z-dn.net/?f=%5Crho%3D%5Cdfrac%7B0%2C430263%5Ctimes%202.015%20%7D%7B0.082%5Ctimes%20321.15%7D%5C%5C%5C%5C%5Crho%3D0.033~g%2FL)
Answer:
![24540\frac{mg}{m^3}](https://tex.z-dn.net/?f=24540%5Cfrac%7Bmg%7D%7Bm%5E3%7D)
Explanation:
Hello,
In this case, since the 3% by volume is represented as:
![\frac{3L\ CO}{L\ gas}](https://tex.z-dn.net/?f=%5Cfrac%7B3L%5C%20CO%7D%7BL%5C%20gas%7D)
By using the ideal gas equation we compute the density of CO:
![\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7BMP%7D%7BRT%7D%20%3D%5Cfrac%7B28g%2Fmol%2A1atm%7D%7B0.082%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%2A298K%7D%3D%200.818g%2FL)
Then we apply the conversion factors as follows:
![=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B3L%5C%20CO%7D%7B100L%5C%20gas%7D%2A%5Cfrac%7B0.818g%5C%20CO%7D%7B1L%5C%20CO%7D%20%2A%5Cfrac%7B1000mg%5C%20CO%7D%7B1g%5C%20CO%7D%20%2A%5Cfrac%7B1000L%5C%20gas%7D%7B1m%5E3%5C%20gas%7D%20%5C%5C%5C%5C%3D24540%5Cfrac%7Bmg%7D%7Bm%5E3%7D)
Regards.