In a healthy pond, the temperature is 16°C (61°F). What is the most likely pH of this pond?

What is the net cell reaction for the cobalt-silver voltaic cell? express your answer as a chemical equation?

slava [35]

Answer: The net ionic equation for the cobalt-silver voltaic cell is $Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)$

Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in $Co(NO_3)_3$ solution ( which means that $Co^{3+}$ are present in the solution) and other half of the cell consists of the Ag electrode immersed in $AgNO_3$ solution ( which means that $Ag^+$ is present in the solution)

The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a cathode.

At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.

At Anode : $Co(s)\rightarrow Co^{3+}(aq.)+3e^-$

At Cathode: $[Ag^+(aq.)+e^-\rightarrow Ag(s)]\times 3$

Net ionic equation: $Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)$

6 0

3 years ago

By which process is a precipitate most easily separated from the liquid in which it is suspended

Gelneren [198K]

<span>Filtration, if its a precipitate that means its insoluble. </span>

7 0

3 years ago

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Aqueous sulfuric acid will react with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . Suppose 0.98 g

cestrela7 [59]

Answer:

0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.

Explanation:

Mass of sulfuric acid = 0.98 g

Moles of sulfuric acid = $\frac{0.98 g}{98 g/mol}=0.010 mol$

Mass of sodium hydroxide = 0.240 g

Moles of sodium hydroxide = $\frac{0.240 g}{40 g/mol}=0.0060 mol$

$H_2SO_4(aq)+2NaOH(s)\rightarrow Na_2SO_4(aq)+2H_2O(l)$

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :

$\frac{1}{2}\times 0.0060 mol=0.0030 mol$ of sulfuric acid

As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.

So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.

According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :

$\frac{1}{2}\times 0.0060 mol=0.0030 mol$ of sodium sulfate

Mass of 0.0030 moles of sodium sulfate :

0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g

0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.

4 0

3 years ago

15.5 g of an unknown metal at 165.0°C is dropped into 150.0mL of H2O at 23.0°C in a coffee cup calorimeter. The metal and H2O re

tino4ka555 [31]

Answer:

Specific heat capacity of metal is 2.09 j/g.°C.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of metal = 15.5 g

Initial temperature = 165.0°C

Initial temperature of water = 23.0°C

Final temperature = 30.0°C

Specific heat capacity of metal = ?

Specific heat capacity of water = 4.184 J/g°C

Volume of water = 150.0 mL or 150.0 g

Solution:

Formula:

- Qm = +Qw

Now we will put the values in formula.

-15.5 g × c × [ 30.0°C - 165.0°C] = 150 g × 4.184 J/g°C × [ 30.0°C - 23.0°C]

15.5 g × c × 135°C = 4393.2 j

2092.5 g.°C × c = 4393.2 j

c = 4393.2 j/2092.5 g.°C

c = 2.09 j/g.°C

4 0

3 years ago

Consider the balanced chemical reaction below. When the reaction was carried out, the calculated theoretical yield for carbon di

jeka94

Answer:

Percent Yield = 94.237%

Explanation:

CO = Carbon Dioxide = Molar Mass 28g/mol

C = Carbon = 12g/mol

O = Oxygen = 16g/mol

Theoretical yield = 93.7 grams

Actual yield = 88.3 grams

Percent yield = (actual yield /theoretical yield )x100

Percent Yield = (88.3/93.7)x100

Percent Yield = 94.237%

8 0

3 years ago

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