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Brrunno [24]
3 years ago
15

Para la limpieza, a veces las amas de casa disuelven en vinagre bicarbonato de sodio, al hacerlo se absorbe calor y sentimos el

reciente frío. Tipo de reacción?
Chemistry
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

exotermicas

Explanation:

You might be interested in
Water molecules contain what type of bonds
Semenov [28]

Answer:

Hydrogen and oxygen bonds

Explanation:

8 0
3 years ago
Read 2 more answers
A 40 g gold coin is cooled from 50°C to 10°C (CAu is 0.13 J/g-°
Debora [2.8K]
When the Heat gain or lose = the mass * specific heat * ΔT

and when we have the mass of gold coin= 40 g 

and the specific Heat of gold=  0.13 J/g°

and ΔT = (Tf- Ti) = 10°C - 50°C = -40 °C

so by substitution:

∴Heat H = 40 g * 0.13 J/g° * -40
               = - 208 J
4 0
3 years ago
What is the molar solubility in water of ag2cro4 ? (the ksp for ag2cro4 is 8 x 10-12. )
nikitadnepr [17]

The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

<h3>How do you define Solubility ?</h3>

The measure of the degree to which a substance gets dissolved in a solvent to become a solution.

The formula for determination of molar solubity is

\rm K_{sp} =  [A^+]^a [B^-]^b

\rm K_{sp}          = solubility product constant

\rm [A^+]^a  =     cation in an aqueous solution

\rm  [B^-]^b  = anion in an aqueous solution

a, b          = relative concentrations of a and b

We have the data given as

\rm K_{sp} for Ag₂CrO₄ is 8 x 10⁻¹²

For Silver chromate , the solubility would be only one-half of the Ag⁺ concentration.

We denote the solubility of Ag₂CrO₄ as S mol L⁻¹.

Then for a saturated solution, we have

[Ag⁺]=2S

[CrO₂⁴⁻]=S

the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction

(2S)²(S)=4S³ = 8 * 10⁻¹²

S=∛ (2*10⁻¹²)

S= 1.26 * 10⁻⁴ M

2S = 2.52 * 10⁻⁴ M

Therefore the molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

To know more about Solubility

brainly.com/question/8591226

#SPJ4

4 0
2 years ago
Read 2 more answers
K2so4 is a strong electrolyte. determine the concentration of each of the individual ions in a 0.450 m k2so4 solution.
amid [387]

<em>Answer:</em>

  • Conc. of K+ ions = 0.90 M
  • Coc. of SO4∧-2 = 0.45 M

<em>Explanation:</em>

<em>Data Given:</em>

Conc. of H2SO4 = 0.450

As sulphoric acid is a strong electrolyte, it completely dissociate into ions.

H2SO4 ⇆   2K+   +   SO4∧-2

.450 M K2SO4 means that there is .450 mols of K2SO4 in every liter of solution.

                      K2SO4  :  K+                                          K2SO4  : SO4∧-2

                          1      =     2                                                   1     =    1

                     0.450   =   2× 0.450 = 0.90                     0.450 =  0.450×1 = 0.450

<em> Result:</em>

Conc. of potassium ion will be 0.90M    

Coc. of sulphate ions will be 0.45 M

8 0
3 years ago
What is the number of moles of solute in a .3 molality solution containing .10 kg of solvent?
denpristay [2]
Concentration can be expressed in different forms: molarity, molality, normality, percentage, part per million and many more. For molality, it is a unit of concentration expressed as moles of solute per kilogram of solvent. Therefore,

0.3 = moles solute/0.10 kg solvent
moles solute = 0.03 moles
4 0
4 years ago
Read 2 more answers
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