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3 years ago

Please help quickly as possible thank you :)

Chemistry

1 answer:

WARRIOR [948]3 years ago

4 0

Answer:

moving object transfers some to the stationary object causing it to move a it. remember that momentum is always conserved though - it is the same at the start before the event and after it.

Explanation:

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An element has an atomic number of 78. the number of protons and electrons in a neutral atom of the element would be _____.

Maurinko [17]

78 and 78. An atom of the element has 78 electrons and 78 protons.

The atomic number is 78, so the atom has 78 protons (+).

If the atom is neutral, it must contain 78 electrons (-).

5 0

4 years ago

A sample of hexane (C6H14) has a mass of 0.580 g. The sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a s

Talja [164]

Answer: The enthalpy of the reaction is -4134.3 kJ/mol

Explanation:

To calculate the heat absorbed by the calorimeter, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed

m = mass of calorimeter = 1.900 kg = 1900 g (Conversion factor: 1 kg = 1000 g)

c = heat capacity of calorimeter = 3.21 J/g.K

$\Delta T$ = change in temperature = 4.542 K

Putting values in above equation, we get:

$q=1900g\times 3.21J/g.K\times 4.542K=27701.66J=27.7kJ$

Heat released by the calorimeter will be equal to the heat absorbed by the reaction.

Sign convention of heat:

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of hexane = 0.580 g

Molar mass of hexane = 86.18 g/mol

Putting values in above equation, we get:

$\text{Moles of hexane}=\frac{0.580g}{86.18g/mol}=0.0067mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

q = amount of heat released = -27.7 kJ

n = number of moles of hexane= 0.0067 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{-27.7kJ}{0.0067mol}=-4134.3kJ/mol$

Hence, the enthalpy of the reaction is -4134.3 kJ/mol

5 0

3 years ago

For each molecule of glucose processed during glycolysis, the net yield is ____. 1. two molecules of NADH, two of ATP, and two o

Lana71 [14]

Answer: 1. two molecules of NADH, two of ATP, and two of pyruvate

Explanation:

During glycolysis 4 molecules of ATP are synthesized by two substrate level phosphorylation (first in step 6 conversion of 1,3-Bisphospho glycerate to 3-Bisphospho glycerate by 1,3-Bisphospho glycerate kinase produces 2 molecules of ATP . Secondly 2 molecules of ATP is produced in step 9 by pyruvate kinase). But 2 molecules of ATP are used in step 1 and 3 by hexokinase and phospho fructo kinase respectively, hence a net yield of only two ATP.

2 molecules of NADH is produced in step 5 by Glyceraldehyde-3-phosphate dehydrogenase.

The end product of glycolysis is 2 molecules of pyruvate.

5 0

4 years ago

Read 2 more answers

Specific heat capacity is _____.

melisa1 [442]

Answer:

all of this

Explanation:

4 0

3 years ago

Imagine that you have a 7.00 L gas tank and a 3.50 L gas tank. You need to fill one tank with oxygen and the other with acetylen

GaryK [48]

Answer:

We should fill the acetylene tank to a pressure of 100 atm

Explanation:

Step 1: Data given

Volume tank 1 = 7.00 L

Tank 1 is filled with oxygen and has a pressure of 125 atm

Volume tank 2 = 3.50 L

Step 2: The balanced equation

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

Step 3: Calculate the pressure of acetylene

p(oxygen) * V(Oxygen) = n(Oxygen) * R * T

p(Acetylene) * V(Acetylene) = n(Acetylene) * R * T

We can assume both tanks are at the same temperature, so we can write this as followed:

p(Oxygen)* V(Oxygen) / p(Acetylene)*V(Acetylene) = n(Oxygen) / n(Acetylene)

⇒with n(Oxygen) / n(Acetylene) = 5/2

⇒with p(Oxygen) = 125atm

⇒V(Oxygen) =7L

⇒V(Acetylene) = 3.5L

⇒ this gives us: (125 * 7) / (P(Acetylene) * 3.5) = 5/2

p(Acetylene) = 100 atm

We should fill the acetylene tank to a pressure of 100 atm

7 0

4 years ago

Please help quickly as possible thank you :) ​

Please help quickly as possible thank you :)