Answer:
The answer to your question is HCl + NaOH ⇒ NaCl + H₂O
Explanation:
Data
Double displacement reaction
Balanced chemical reaction
HCl + NaOH ⇒ NaCl + H₂O
Reactants Elements Products
1 Chlorine (Cl) 1
1 Sodium (Na) 1
2 Hydrogen (H) 2
1 Oxygen (0) 1
As we can see, the reaction is balanced and the coefficients of all reactants and products are 1, but the number is not written in a balanced reaction.
Atomic weight is Ar of the atom (what you see on the periodic table)
atomic weight<span> is relative </span>atomic mass, so yeah same thing
<span>As can be seen from the 1st MO diagram on the website the overlap of the H1s AO on one H atom with the H1s AO on another H atom results in a Ď MO at lower energy to the constituent AOs, and a Ď* MO at higher energy than the starting AOs. Each MO can hold two eâ»s so the H2^- has the configuration Ď(2eâ») Ď*(1eâ») or Ď(↑↓) Ď*(↑) Bond Order = ½[ÎŁ (bonding eâ») - ÎŁ (antibonding eâ»)]
bo = ½[ÎŁ (2eâ») - ÎŁ (1 eâ»)] = 0.5 the H2^- is predicted to be bound.
The lowest energy electronic transition is Ď â†’ Ď*: Ď(↑↓) Ď*(↑) → hν → Ď((↑)) Ď*(↑↓)
This guy has a bond order of -0.5 and hence is unbound.</span>
I believe its
a)224000
b)0.000000015
c)0.655
d)9000
Answer:
.
Explanation:
Electron orbitals in an atom (e.g., 
) are denoted with:
- A number, denoting the shell (principal energy level) of this orbital, and
- A letter, denoting the shape of this orbital (
, 
, 
, etc.)
There are two aspects to consider when finding the electron configuration of an atom:
- The number of electrons that each type of orbitals could hold, and
- The order in which the orbitals are filled.
The orbital in each shell could hold up to 
electrons (one 
orbital per shell, with up to two electrons.)
The orbitals in each shell could hold up to 
electrons (three 
orbitals per shell, with up to two electrons in each orbital.)
The orbitals in each main shell could hold up to 
electrons (five 
orbitals per shell, with up to two electrons in each orbital.)
Refer to the order in which the orbitals are filled (Aufbau principle.)
- The first orbital to be filled would be (the orbital of the first shell,) accommodating up to
electrons. - The second orbital to be filled would be
(the orbital of the second shell,) accommodating up to electrons.
All four electrons of Beryllium are thus assigned to the and orbitals. In a ground-state Beryllium atom, orbitals 
and beyond would contain no electrons.
Notation:
- Two electrons in the orbital:
(the superscript denotes the number of electrons in this orbital (or group of orbitals).) - Two electrons in the orbital:
.
Write the non-empty orbitals in the order by which they are filled:
.
