Hope this helps <span>A vector always consists of a direction and magnitude. F</span>
Al, since it is the only metal in that list
Answer:
Volume of AgNO₃ = 4.9 ml (Approx)
Explanation:
Given:
Total solution = 75 ml
Volume of AgNO₃ = 6.5%
Find:
Volume of AgNO₃
Computation:
Volume of AgNO₃ = Total solution x Volume of AgNO₃
Volume of AgNO₃ = 75 x 6.5%
Volume of AgNO₃ = 4.875
Volume of AgNO₃ = 4.9 ml (Approx)
Answer:
The mass of xenon in the compound is 2.950 grams
Explanation:
Step 1: Data given
Mass of XeF4 = 4.658 grams
Molar mass of XeF4 = 207.28 g/mol
Step 2: Calculate moles of XeF4
Moles XeF4 = mass XeF4 / molar mass XeF4
Moles XeF4 = 4.658 grams / 207.28 g/mol
Moles XeF4 = 0.02247 moles
Step 3: Calculate moles of xenon
XeF4 → Xe + 4F-
For 1 mol xenon tetrafluoride, we have 1 mol of xenon
For 0.02247 moles XeF4 we have 0.02247 moles Xe
Step 4: Calculate mass of xenon
Mass xenon = moles xenon * molar mass xenon
Mass xenon = 0.02247 moles * 131.29 g/mol
Mass xenon = 2.950 grams
The mass of xenon in the compound is 2.950 grams
