Yes, that's correct. The note "A" (which is used to tune the other strings of the guitar) corresponds to a frequency of 440 Hz.
P=change in E/t
Change in E=p*t
=15*3
=45
The answer is 45J.
When the gold cube is immersed in mercury, the tension in the string in Newtons is 3.142N.
<h3>What is tension?</h3>
Tension is the force acting on the linear object like string, chain or rope due to pulling.
Volume of gold V = mass / density
V = 1.18 /19.3x 10³ =61.1 x 10⁻⁶ m³
Tension in the string after immersing will be
T = [ρ(Gold) -ρ(Hg)] g. V
T =[ 19.3x 10³ - 13.6 x 10³] x 9.81 x 61.1 x 10⁻⁶
T =3.416 N
Thus, the tension in the string is 3.42 N.
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Answer:
216 m
Explanation:
Assuming a straight line:
Δx = vt
Δx = (12 m/s) (18 s)
Δx = 216 m