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Scilla [17]
3 years ago
10

Determine the magnitude of the force between two 42 m-long parallel wires separated by 0.03 m, both carrying 6.3 A in the same d

irection.
Physics
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

length of the two parallel wires, L = 42 m

distance between the two wires, r = 0.03 m

current in both wires, I₁, I₂ = 6.3 A

Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F =   0.0111 \ N

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.

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qwelly [4]

Hello there.

1.986*10^6

10^6=1,000,000

1.986*1,000,000

<u><em>Answer=1,986,000</em></u>

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2 years ago
(Q008) Magnetic anomalies are a. found only on the seafloor. b. measured with an instrument called an inclinometer. c. defined a
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xxTIMURxx [149]

Answer:

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Explanation:

Given parameters:

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To solve this problem, we use one of the motion equations.

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v is the final velocity

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cestrela7 [59]

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Explanation:

Given:

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