What changes happen to ions which are attracted to cathode during electrolysis?
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Answer: Concentrations of cyclohexane and methylcyclopentane at equilibrium are 0.0223 M and 0.0027 M respectively
Explanation:
Moles of cyclohexane = 0.069 mole
Volume of solution = 2.8 L
Initial concentration of cyclohexane =
The given balanced equilibrium reaction is,
cyclohexane ⇔ methylcyclopentane
Initial conc. 0.025 M 0
At eqm. conc. (0.025-x)M (x) M
The expression for equilibrium constant for this reaction will be,
K= methylcyclopentane / cyclohexane
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.0027
Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M
Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M
Answer:
Molecular formula
Explanation:
Molecular formula in the first place is required to understand which compound we have. We then should refer to the periodic table and find the molecular weight for each atom. Adding individual molecular weights together would yield the molar mass of a compound.
Then, dividing the total molar mass of a specific atom by the molar mass of a compound and converting into percentage will provide us with the percentage of that specific atom.
E. g., calculate the percent composition of water:
- molecular formula is
;
- calculate its molar mass: [tex]M = 2M_H + M_O = 2\cdot 1.00784 g/mol + 16.00 g/mol = 18.016 g/mol;
- find the percentage of hydrogen: [tex]\omega_H = \frac{2\cdot 1.00784 g/mol}{18.016 g/mol}\cdot 100 \% = 11.19 %;
- find the percentage of oxygen: [tex]\omega_O = \frac{16.00 g/mol}{18.016 g/mol}\cdot 100 \% = 88.81 %.