Visual representation of covalent bonding indicating the valence shell electrons in the molecule, lines represents the shared pair of electron and pair of electrons that are not involved in bonding are represented as dots(lone pairs) are known as Lewis structures.
Compound formation takes place in order to complete the octet of each element that is according to octet rule, each atom forms bond with other atom in order to complete their octet that is to get eight electrons in its valence shell and attain stability.
An organic compound of the form 
is known as ketene.
The given ketene is 
.
The number of valence electron of:
The number of valence electrons in = 
2 electrons are involved in each single bond between carbon and hydrogen and 4 electrons are involved in each double bond formed between carbon-carbon and carbon-oxygen. Hence, the total number of electrons involved in bond formation are 12 and rest 2 pair of electrons are present on oxygen as lone pair of electrons.
Therefore, the attached image is the Lewis structure of .
when you type your answer ... your body gets sick rid of waste through the skin
The balanced dissociation equation for Cs₂CO₃ is:
Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)
A dissociation equation is an equation showing the available ions present in a solution.
To obtain the dissociation equation, the compound must be dissolved in water to produce an aqueous solution.
The dissociation equation for Cs₂CO₃ can be written as follow
Cs₂CO₃(aq) —> Cs⁺(aq) + CO₃²¯(aq)
Learn more about dissociation equation: brainly.com/question/1903354
We know that acids have a pH of under 7.
We also need to:
Set up an ICE table for the chemical reaction. Solve for the concentration of H3O+ using the equation for pH Use the concentration of H3O+ to solve for the concentrations of the other products and reactants.
Answer: 15.8 g of 
will be required to produce 1.60 grams of 
Explanation:
To calculate the moles :
According to stoichiometry :
As 1 mole of is given by = 2 moles of
Thus 0.05 moles of is given by =
of
Mass of 
Thus 15.8 g of will be required to produce 1.60 grams of
