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Ahat [919]
1 year ago
10

7. Draw the structures for the following hydrocarbons.HydrocarbonCyclohexane(C6H12)Cyclohexene(C6H10)StructureHydrocarbonBenzene

(C6H6)Toluene(C7H8)Structure
Chemistry
1 answer:
Alborosie1 year ago
7 0

So,

Let's draw the structures for the following hydrocarbons:

Cyclohexane

We can draw it using the fact that it is a cycloalkane with six carbons:

Cyclohexene

It also contains six carbons with a hexagonal form, but the difference is that there's double bond on it:

Benzene

It has six carbons but there's an alternating double bond as follows:

Toluene

It has the same structure as benzene but it is bonded to a methyl group outside the benzene:

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Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i
kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy

As can be seen from the reaction stoichiometry that:

<u>6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.</u>

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus, moles of carbon dioxide are:

moles_{CO_2} = \frac{120 g}{44 g/mol}

moles_{CO_2} = 2.7273 mol

As mentioned:

<u>6 moles of carbon dioxide</u> gas can be produced from <u>1 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>1 mole of carbon dioxide</u> gas can be produced from <u>1/6 mole of oxygen gas</u> in the process of metabolism of glucose.

<u>2.7273 mole of carbon dioxide</u> gas can be produced from <u>\frac{1}{6} \times 2.7273 moles of oxygen gas</u> in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass\ of\ oxygen\ gas = Moles \times Molar mass}

Mass\ of\ oxygen\ gas = 0.4545 \times 32}

Mass\ of\ oxygen\ gas = 14.544 g

<u>14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.</u>

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Explanation:

An explosion is a combustion and a quick reaction, That makes it rapid

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What number represents water becoming water vapor in this diagram
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the answer is <u>"A" 1</u>

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Which of the following is the correct scientific notation for 0.000056?
svet-max [94.6K]
Hi,

0.000056 = 5.6 \times  {10}^{ - 5}

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r3t40
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Which of the following metals would be the best for the new frying pan?
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Answer:

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