When orthobromoanisole is treated with sodamide (NaNH₂) and ammonia (NH₃), benzyne is formed and the tripple bond is formed between C₂-C₃ carbon atoms of benzene ring. Then NH₂⁻ can attack at ortho position as well as meta position.
The reaction takes place in three steps. Step-1:The amide NH₂⁻ ion attacks the H
-atom that is ortho to C3
, generating a carbanion. Step-2:Loss of Br
- to form a benzyne intermediate.Step-3:Addition of NH₂⁻ ion. The strain caused by a triple bond in a benzene ring can be relieved by a nucleophilic addition of NH₂⁻.
Two isomeric products are formed: (1) <em>o</em>-methoxyaniline and (2) <em>m</em>-methoxyaniline. The structures of both the isomeric products are given in diagram.
The classical bonding model which best explains the bonding in the compound NaH₂PO₄ is Hydrogen bonding.
<h3>What is Classical bonding model ?</h3>
By classical, we mean models that do not take into account the quantum behavior of small particles, notably the electron.
These models generally assume that electrons and ions behave as point charges which attract and repel according to the laws of electrostatics.
Sodium dihydrogen phosphate (NaH₂PO₄) is monoclinic, In which, the four independent hydrogen atoms were located on a difference map; they are involved in four O … O Hydrogen-bonds of length 2.654 (2), 2.589 (2), 2.559 (2), and 2.500 (2) Å.
The short contact (2.500 Å), which is not astride any symmetry element, is of the type O-H … O (asymmetrical).
The distorted coordination polyhedra of the sodium atoms are discussed in the light of recent theories on electrostatic balance.
Hence, the classical bonding model which best explains the bonding in the compound NaH₂PO₄ is Hydrogen bonding.
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Answer:
poisoning, breathing problems, skin rashes, allergic reactions, allergic sensitisation, cancer, and other health problems from exposure.
Explanation:
many hazardous chemicals are also classified as dangerous goods.
