solution of potassium chlorate,
K
C
I
O
3
, has 20 grams of the salt dissolved in 100 grams of water at 70 C. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?
Explanation:
First Question:
The equation is given as;
2KClO3 --> 2KCl + 3O2
2 mol of KClO3 produces 2 mol of KCl
Converting 7.6 g of KCl to mol;
Number of moles = Mass / Molar mass = 7.6 / 74.5513 = 0.1019
2 mol = 2 mol
x mol = 0.1019
solving for x;
x = 0.1019 mol of KClO3
converting to mass;
Mass = Number of mol * Molar mass = 0.1019 * 122.55 = 12.48
Correct option = B. 12.5 g
Second Question
The equation is given as;
1N2 + 3H2 --> 2NH3
3 mol of H2 produces 2 mol of NH3
Converting 34.06g of NH3 to mol;
Number of moles = Mass / Molar mass = 34.06 / 17.031 = 2 mol
3 mol = 2 mol
x mol = 2 mol
Solving for x;
x = 6 / 2 = 3 mol of H2
Converting 3 mol H2 to g;
Mass = Number of moles * Molar mass = 3 * 2.016 = 6.048g
Correct option: B. 6.05g
Average kinetic molecular energy is actually defined by temperature, so any gas, no matter the volume or pressure, will have the same average kinetic molecular energy as long as its temperature is the same. Therefore, Gases A, B, and D all have the same average molecular kinetic energy, since they are at 12<span>°C.</span>
Physical change is the answer.
