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Levart [38]
2 years ago
6

I messed up Èeeeeeeeeeeeeeeeeeeee

Chemistry
1 answer:
Triss [41]2 years ago
6 0

Answer:

o

Explanation:

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The combination of all the forces on an object is called?
krek1111 [17]

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net force

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1. Why does light have different effects on various materials?
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Light basically evaporates pigments such as colored paper. Exposed pigment fading is kind of like getting colored paper wet. It will fade and bleed.
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Analyze the bonds of CCl4. What is the shape of the CCl4 molecule? Is it symmetrical? Does this mean that the CCl4 molecule is p
Crank

C-Cl bond is polar.


As Cl is more electronegative than C,  

Cl pulls the shared electrons towards its side making the C-Cl bond polar.


Polar meaning C gets a partial positive charge and Cl gets a partial negative charge. Thus C-Cl bond becomes polar.


CCl4 molecule is tetrahedral.

And its shape is symmetrical.


That means its similar on all corners or all planes and it can be cut into equal halves from any plane.


C-Cl bond is polar.But the C-Cl polairty gets cancelled out as its pulled equally from all sides.


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The cells of all organisms must produce energy in order for the cell to survive and function. The diagrams below show
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3 years ago
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
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