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Naddika [18.5K]
3 years ago
12

When you see the word heptahydrate, what number should be written in front of the formula for water? 5 6 7 8?

Chemistry
1 answer:
Yuki888 [10]3 years ago
8 0
Hept for 7, hence the number is seven.
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1. Destiny is working in the lab with a filter. She has a mixture of Aluminum Phosphate (AlPO4)
tester [92]
B Aipo, is insoluble in water
7 0
2 years ago
What mass of silver oxide, Ag2O is required to produce 25.0 g of silver sulfadiazine, AgC10H9N4SO2, from the reaction of silver
Wittaler [7]

Answer:

8.1107 g

Explanation:

The given reaction:

2C_{10}H_{10}N_4SO_2+Ag_2O\rightarrow 2AgC_{10}H_9N_4SO_2+H_2O

Given that:

Mass of silver sulfadiazine = 25.0 g

Molar mass of silver sulfadiazine = 357.14 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{25.0\ g}{357.14\ g/mol}

Moles= 0.07\ mol

From the reaction,

2 moles of silver sulfadiazine are formed from 1 mole of silver oxide

So,

1 mole of silver sulfadiazine are formed from 1/2 mole of silver oxide

0.07 mole of silver sulfadiazine are formed from 1/2*0.07 mole of silver oxide

Moles of silver oxide = 0.035 moles

Molar mass  of silver oxide = 231.735 g/mol

Mass = Moles * Molar mass = 0.035 moles * 231.735 g/mol = 8.1107 g

4 0
4 years ago
Which of the following is the correct formula for copper (I) sulfate trihydrate? CuSO4 · 3H2O
PilotLPTM [1.2K]
It is either the 3rd answer or the 4th answer. Both are correct ways to write hydrates, but I was taught the 4th way. Just make sure this answer matches the format of the examples your teacher gave you.
6 0
3 years ago
Read 2 more answers
4. What helps syrup and honey flow more easily out of a measuring cup?*
mixas84 [53]
You can use grease or oil
7 0
3 years ago
A mixture of bases can sometimes be the active ingredient in antacid tablets. If 0.4884 g of a mixture of Al(OH)3 and Mg(OH)2 is
Nitella [24]

Answer:

54.7%

Explanation:

The reaction of neutralization will be:

Al(OH)₃ + Mg(OH)₂ + 5HNO₃ → Al(NO₃)₃ + Mg(NO₃)₂ + 5H₂O

The number of moles of HNO₃ added is the concentration multiplied by the volume (17.12 mL = 0.01712 L)

n = 1*0.01712 = 0.01712 mol

For the stoichiometry:

1 mol of Al(OH)₃  ---------- 5 moles of HNO₃

x ----------------------------------0.01712 mol

By a simple direct three rule:

5x = 0.01712

x = 3.424x10⁻³ mol of Al(OH)₃

For the stoichiometry, the number of moles of Mg(OH)₂ will also be 3.424x10⁻³.

The molar masses are:

Al(OH)₃: 27 g/mol of Al + 3*16 g/mol of O + 3*1 g/mol of H = 78 g/mol

Mg(OH)₂: 24 g/mol of Mg + 2*16 g/mol of O + 2*1 g/mol of H = 58 g/mol

The mass is the molar mass multiplied by the number of moles:

Al(OH)₃: 78*3.424x10⁻³ = 0.2671 g

Mg(OH)₂: 58*3.424x10⁻³ = 0.1986 g

The mass % of Al(OH)₃ in the mixture is its mass divides by the mass of the mixture, multiplied by 100%:

(0.2671/0.4884)x100% = 54.7%

5 0
3 years ago
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